A wildlife study is designed to find the mean weight of salmon caught by an Alaskan fishing company. find the minimum sample size needed in order to construct a 95% confidence interval for the mean weight of such Salmon, to within 0.20 pounds. Assume that standard deviation 2.10.

Q: In order to construct a confidence interval on the difference between means, you need to assume that…

A: Solution: Assumptions for constructing a confidence interval on the difference between means are…

Q: The operator of a nuclear power plant requires fuel rods to have a mean percentage of enrichment of…

A:

Q: How large a sample should be selected to provide a 99% confidence interval with a margin of error of…

A: Given,standard deviation(σ)=50margin of error (E)=10α=1-0.99=0.01α2=0.005Z0.005=2.58

Q: Which of the following would increase the width of a confidence interval for a population mean?

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Q: The Ball Corporation's beverage can manufacturing plant in Fort Atkinson, Wisconsin, uses a metal…

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Q: In a study of government financial aid for college students, it becomes necessary to estimate the…

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Q: We take a sample of 50 people and obtain a sample mean of 147 pounds with a standard deviation of 15…

A: We have given that  Sample size n = 50 Sample mean = 147 Standard deviation = 15 90%confidence…

Q: In an examination of purchasing patterns of shoppers, a sample of 16 shoppers revealed that they…

A: From the given information, sample mean, x̅=54 Population standard deviation, σ=21 Sample size n =16…

Q: In a random sample of twelve ​people, the mean driving distance to work was 21.5 miles and the…

A: Solution

Q: A random sample of 51 four-year-olds attending day care centers provided a yearly tuition average of…

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Q: With a large sample size such as n = 100, we do not need to assume the distribution is normal in…

A: True.Central limit theorem:In the process of selecting a simple random samples of size n from a…

Q: If the sample has standard deviation 2.1, what is a reasonable approximation to the range of this…

A: It is given that the standard deviation of the data is 2.1.

Q: In a random sample of 20 days, a newspaper dealer sold on the average 345 newspapers per day with a…

A: X̄ = 345 n = 20, σ = 20

Q: A weekly tabloid reported that the average income of its subscribers is $39,100. Assume this…

A:

Q: Find the 98% confidence interval for the difference between the means of the two populations

A: Given that sample size n = 18 Mean difference = 22.9 And SD sd = 2.2 The critical value of t at (n -…

Q: When planning to construct a 95% confidence interval for a population mean such that it is within…

A: Given data, E=1/8=0.125 Let p=0.5 z-value at 95% confidence is Zc=1.96 n=?

Q: In a random sample of ten ​people, the mean driving distance to work was 18.1 miles and the standard…

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Q: Construct a 90​% confidence interval for the population standard deviation σ at Bank B.

A: The descriptive analysis is conducted using EXCEL. The software procedure is given below: Enter the…

Q: Use the given confidence interval to find the margin of error and the sample mean.

A:

Q: In a random sample of ten people, the mean driving distance to work was 21.8 miles and the standard…

A: Given,sample size(n)=10mean(x)=21.8standard deviation(σ)=6.4α=1-0.99=0.01α2=0.005degrees of…

Q: Calculate a 90% confidence interval for the mean of the population, supposed normal, from which…

A: Given, Heights 63 63 66 67 68 69 70 70 71 71 Let X be height of  animal…

Q: A survey of 31 accountants shows the average salary is $65,000 with a population std deviation of…

A: Given : Sample size, n= 31 Mean = $65000 Population standard deviation = 7000

Q: How large a sample should be selected to provide a 95% confidence interval with a margin of error of…

A: Given that, Confidence Interval = 95% Margin of error, M.E. = 4 Population Standard deviation, σ =…

Q: If a sample has 20 observations and a 90% confidence estimate for μ is needed, the appropriate…

A:

Q: Construct a 95% confidence interval for the population mean, μ. Assume the population has a normal…

A: Construction of the test statisticXi~Nμ , O2 , i =cn , independently⇒ x  ~N μ σ2n n-1S2σ2 ~ Xn-12…

Q: Consumers may be interested in whether the cost of a particular calculator varies from store to…

A: Given, Sample size, n = 43 Sample mean,  = 84 Sample standard deviation, s = 12 Population standard…

Q: Use Table V in Appendix A to determine the t-percentile that is required to construct each of the…

A: It is given that the degrees of freedom is 24 and the confidence level is 0.999.

Q: A narrower confidence interval for a population parameter with a given confidence level can be…

A: Here we need to determine whether the given statement is true or false. First we need to find if…

Q: For a given sample, a 50% confidence terval for the population mean is narrower than a 90%…

A: For  a given sample size and population standard deviation, the interval estimation of the…

Q: How large a sample should be selected to provide a 99% confidence interval with a margin of error of…

A:

Q: 3. Another engineer studies the strength of cables, which has a known population standard deviation…

A: Here we need to obtain the minimum sample size required to obtain a 97% confidence interval.

Q: n a crash test of 15 troopers, collision repair costs are found to have a distribution that is…

A: The summary of the statistics is, x¯=1800,s=950,n=15 The degree of freedom is, df =n -1     =15-1…

Q: Find the desired sample size for a 90% confidence interval with a margin of error equal to 0.03

A: Given information: Denote the population proportion as p. Since, the preliminary estimate of the…

Q: A professor at a local community college is interested in studying the amount of hours that a…

A: See the handwritten solution

Q: Find the error bound for an unknown population mean or the margin of error that corresponds to a 85%…

A: Find the error bound for an unknown population mean or the margin of error that corresponds to a 85%…

Q: In a random sample of twelve ​people, the mean driving distance to work was 18.8 miles and the…

A: From the given information we want to construct 90% confidence interval.

Q: (b) A sample of size 15 drawn from a normally distributed population has sample mean 35 and sample…

A:

Q: Find the 95% confidence interval for the variance and standard deviation of the heights of maple…

A: Construct the 95% confidence interval for the variance. Obtain the critical values. The standard…

Q: Provide an explanation as to why it would be very unlikely that a different sample of size n=30…

A: Given: n=30

Q: The cell phone conversations of a random sample of 50 students has a standard deviation of 9.7…

A: Given: n=50σ=9.7CI=90%=0.90

Q: Given a certain 98% confidence interval is (0.05,0.29), what is the exact value of the margin of…

A: We have given that 98% confidence interval is (0.05,0.29) Since we know that Lower bound = x̅ - E…

Q: Select the correct interpretation of the 95% confidence level t-interval for the mean baseline…

A: The 95% confidence interval for mean baseline 25OHD is (23.6, 39.7). The confidence interval can be…

Q: Assuming a population of interest is approximately normally distributed, construct a 95% confidence…

A: Solution: Let X be the random variable. From the given information, x-bar=30, s=3.5 and n=15.

Q: In a random sample of 38 criminals convicted of a certain​ crime, it was determined that the mean…

A: Given : n= 38.0 , x= 67.0 s= 11.0 At 95.0 % confidence level , z score= 1.96

Q: A wildlife study is designed to find the mean weight of salmon caught by an Alaskan fishing company.…

A:

Q: The average weight of 35 randomly compact automobiles was 2680. The sample standard deviation was…

A: From the provided information, Sample size (n) = 35 Sample mean (x̅) = 2680 Sample standard…

Q: Construct a 99% confidence interval for the population standard deviation σ if a sample of size 11…

A: Confidence Interval: A confidence interval, in statistics, refers to the probability that a…

Q: Given that the population standard deviation is 1, determine the minimum sample size needed in order…

A: Given : population standard deviation = σ = 1 margin of error = E = 0.2 level of confidence = 95% At…

Q: The average weight of 35 randomly selected compact automobiles was 2680 pounds. The sample standard…

A: From the provided information, Sample size (n) = 61 Sample mean (x̅) = 2680 Sample standard…