Please all parts answer.. A vertical sag parabolic curve connects a -6% grade to a +1% that meetsat station 12+720 with an elevation of 63m. The change in grade is 0.7%every 20m. What is the stationing and elevation of the lowest point of thecurve?Group of answer choices12+791.43; Elevation 63.86m11+852.72; Elevation 64.27m13+003.24; Elevation 65.63m14+283.32; Elevation 66.26mA 280m long sag curve connects a -13% grade to a +5% grade. The graderintersects at station 1+460 which elevation of 12.39m. Find the elevationof the first quarter point of the curve.Group of answer choices19.25m27.5m23.07m21.62mCurve having a radius of 155.42m has an intersecting angle of 36"45'. PCis at station 0+750. Find the right angle offset distance to station0+825.50m.Group of answer choices16.48m17.98m19.64m18.55mThe areas in cut of two irregular sections 65m apart are 29 square metersand 68 square meters respectively. Base width is 10m side slope of 3:2.Using Prismoidal correction formula, find the corrected value of cut incu.m between the two stations.Group of answer choices3571.833807.763719.42

Answered: Image /qna-images/answer/f0af5863-2508-4382-88cf-4d4e1f37485f.jpg

A vertical sag parabolic curve connects a -6% grade to a +1% that meets at station 12+720 with an elevation of 63m. The change in grade is 0.7% every 20m. What is the stationing and elevation of the lowest point of the curve? Group of answer choices 12+791.43; Elevation 63.86m 11+852.72; Elevation 64.27m 13+003.24; Elevation 65.63m 14+283.32; Elevation 66.26m

A vertical sag parabolic curve connects a -6% grade to a +1% that meets at station 12+720 with an elevation of 63m. The change in grade is 0.7% every 20m. What is the stationing and elevation of the lowest point of the curve? Group of answer choices 12+791.43; Elevation 63.86m 11+852.72; Elevation 64.27m 13+003.24; Elevation 65.63m 14+283.32; Elevation 66.26m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

12. A sag curve is composed of two parabolic curves. BVC and EVC have elevations 250.30m and 246.30m respectively. The grade of the tangents is -3.5% at BVC (1+300) and +5.5% at EVC (1+800). What is the grade of the common tangent? a) 1.25% c) 0.008% b) 0.08% d) 0.8% 13. Compute the deflection angle at the endpoint of the spiral if the length of spiral is 52m and the degree of the central curve equal to 7.5⁰ a) 3.25⁰ c) 3.52⁰ b) 2.35 d) 2.53 14.
Two tangents having an azimuth of 235° and 277° meet at station 30+28.212 are connected by a 330ft spiral curvewith a 5° circular curve used for light rail transit.a) Determine the difference between the external distance of the spiral and the central curve.b) Determine the minimum super-elevation of the curve at the two-thirds of the spiral with the railway width of 15ft. If g= 32.2 ft/s^2c) Determine the stationing of the S.T.
Part of a 300 m long vertical curve road connecting a rear tangent mile (+1.92%) and a front tangent mile (-2.58%) intersect at its station point (00 + 10) of 21.52 m. what is the level of the highest point on the curve?
The centerline of a proposed road cross section across a smallvalley between station 14+042 (elevation 123.00m) and station 14+080 (elevation 122.50 m). The stationing at the bottom of the valley is 14+057 (elev.111.2). The grade line of the proposed road passes the ground points at the edges of the valley (Sta. 14 +022) and ( 14+080) and the sections. Width of the road base = 10m with sideslope of 2:1. Assume that the sides of the valley slope directly to the lowest point from the edges. Find the cross sectional area of fill at Station 14+057 Compute the volume of fill from station 14+042 to 14+057
topic: fundamentals of surveying A 3% ascending grade meets a descending grade at the vertex at station 2+050 and elevation 100m with a curve elevation of 97.333m below it. The tangents are connected by an unsymmetrical parabolic curve and the vertical offset of the point of tangency from the back tangent is 9.60m. If the length of the second curve is 80m, determine: A.) Length of the 1st Curve = [L1] B.) Stationing of the Highest Point = [StaHP] C.) Elevation of the Highest Point = [ElevHP]
A descending grade at the rate of -5% intersects another grade ascending at the rate of +7% at station 3+170, elevation 125.7m. A vertical curve is to connect the two such that that the urve will clear the boulder located at station 3+155, elevion 127.25m. Calculate the following: a. length of the curve b. the statio of the location of a sewer to be laid c. elevation of the station where the sewer is to be placed.
A certain horizontal curve has a central angle of 42.2°. If STA PC is 18+363 and STA PT is at 18+708, determine the station of PI.
a downgrade of 3.20 meets an upgrade of 4.6 at Sta. 73+180 where the elevation is 998m. A parabolic curve AB, 440m long, connects the grade lines from A at the downgrade B at the upgrade. Find the stationing of B.
An ascending grade of 2.7% intersects another grade at STA 12+598 whose elevation in 582m. The change in grade is -0.15% per 20m station. The two grades are to be connected by a parabolic curve 800m long. Determine the elevation (m) of the summit.
At station 95+220, the center height of the road is 4.5 m cut, while at station 95+300, it is 2.6 m fill. The ground between station 95+220 to the other station has a uniform slope of -6.5%. What is the grade of the road?
Two tangents intersect at v with back tangent having a grade of - 2.75q and forward tangent of 6.25%. A 195m curve lies on the side of PC AND 105 on the other side. Station Ing of V is at 10+535 having an elevation of 102 if a bridge is located above the curve, with its centerline having an elevation of 119m and stationing of 10+580, with underside of the bridge located 120cm below the given election, determine the height of the highest vehicle it can accommodate if the bridge has a width of 12m
A 7.15° horizontal curve has a central angle of 36.7°. If the station of PT is at 25+198, determine the station of PC.