A virus particle which has a 3uC charge is placed in a non-uniform Electric Field. The potential of this electric field is given by the function V = 2x106(x2-x+1) Volts. Assume x=0 as the starting point (a) What is the Electric field at the point ( 50,0) where the distance is measured in cm.  (b)It is known that it requires 10J of energy to vaporize the virus particle. This energy can be generated by moving the virus in this electric field. What distance does the virus need to be moved to achieve this? (c ) How much potential difference is required to make this happen.

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A: Position given = 2.6i^  - 6.2j^ +2.2k^ V (Potential) = 1.5xyz2 E = -(gradient of V)

Q: Consider a conducting sphere with charge q = 4.00 µC/m and radius a = 3.0 cm, coaxial with a…

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A: Here the point A and B at a distance from the origin is rA=3m2+3m2=32 mrB=0m2+2m2=2 m

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A: The change in electric potential can be expressed as follows,

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A: Dear student The electric potential at the center of a semicircular ring is given by: V = KqR Here K…

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Q: Consider two negative charges, -/q/ and -/3q/, held fixed at the base of an equilateral triangel of…

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Q: An object with charge q = -11.00 nC is placed in a region of uniform electric field and is released…

A: Given: Charge, q=-11 nC=-11×10-9 C Work done by the electric field, W=0.5 μJ=0.5×10-6 J Electric…

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A: Hello. Since you have posted multiple questions and not specified which question needs to be solved,…

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A: Basic Details The electric field is equal to negative of derivative of the potential function.

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A: Given :    Electric potential, V = x2y + 3z4

Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.