A voltaic cell is composed of the following 2 half reactions: Mn²+ (aq) + 2e → › Mn(s) Ecell = -1.185 V Cu+ (aq) + e Cu(s) Eell = 0.521 V Determine the non-standard state Ecell at 298 K when Mn²+ (aq) = 0.158 M and Cu+ (aq) = 0.663 M. → V

Chemistry: The Molecular Science
5th Edition
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Author:John W. Moore, Conrad L. Stanitski
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Chapter17: Electrochemistry And Its Applications
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A voltaic cell is composed of the following 2 half reactions:
Mn²+ (aq) + 2e
→
> Mn(s) Ecell = -1.185 V
Cu+ (aq) + e Cu(s) Eell = 0.521 V
Determine the non-standard state Ecell at 298 K when Mn²+ (aq) = 0.158 M and Cu+ (aq) = 0.663 M.
→
V
Transcribed Image Text:A voltaic cell is composed of the following 2 half reactions: Mn²+ (aq) + 2e → > Mn(s) Ecell = -1.185 V Cu+ (aq) + e Cu(s) Eell = 0.521 V Determine the non-standard state Ecell at 298 K when Mn²+ (aq) = 0.158 M and Cu+ (aq) = 0.663 M. → V
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Determine the equilibrium constant, K, for the voltaic cell composed of the following 2 half reactions at
298 K.
2+
Sn²+ (aq) +
+2e → Sn(s) Ecell = -0.136 V
Mn2+
²+ (aq) + 2e¯¯→ Mn(s) Ell-1.19 V
Report your answer in the format 2.4E-3.
1.87E-36
Hint: Decide which half-reaction is the reduction reaction and which one is the oxidation reaction by
looking at Eº; the oxidation reaction should be reversed, and will have the opposite sign.
4.0560949048976E+35
Transcribed Image Text:Score on last try: 0 of 2 pts. See Details for more. You can retry this question below Determine the equilibrium constant, K, for the voltaic cell composed of the following 2 half reactions at 298 K. 2+ Sn²+ (aq) + +2e → Sn(s) Ecell = -0.136 V Mn2+ ²+ (aq) + 2e¯¯→ Mn(s) Ell-1.19 V Report your answer in the format 2.4E-3. 1.87E-36 Hint: Decide which half-reaction is the reduction reaction and which one is the oxidation reaction by looking at Eº; the oxidation reaction should be reversed, and will have the opposite sign. 4.0560949048976E+35
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