A water solution contains 60% Na2S2O2 together with 0.08% soluble impurity. Upon cooling to 10 °C, Na2S₂O25H₂O crystallizes out. The solubility of this hydrate is 1.4 lb Na2S₂O25H₂O/lb free water. The crystals removed carry as adhering solution 0.07 lb solution/lb crystals. These are dried to remove the remaining water (but not the water of hydration). The final dry Na2S₂O25H₂O crystals must not contain more than 0.08% impurity. To meet this specification, the original solution, before cooling, is further diluted with water. On the basis of 50 kg of the original solution, how much water must be added before cooling and what is the percent recovery of Na2S2O2 in the dried crystals?

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