A woman at an airport is towing her 15.0 kg suitcase at constant speed by pulling on a strap at an angle θ above the horizontal (see figure). She pulls on the strap with a 38.5 N force, and the friction force on the suitcase is 20.0 N.A woman holds the strap of a suitcase while pulling it to the right. The strap makes an angle θ measured counterclockwise from the horizontal.(a)Draw a free-body diagram of the suitcase.This answer has not been graded yet.(b)What angle does the strap make with the horizontal (in degrees)? (c)What is the magnitude of the normal force that the ground exerts on the suitcase (in N)?

Question
Asked Oct 28, 2019

A woman at an airport is towing her 15.0 kg suitcase at constant speed by pulling on a strap at an angle θ above the horizontal (see figure). She pulls on the strap with a 38.5 N force, and the friction force on the suitcase is 20.0 N.

A woman holds the strap of a suitcase while pulling it to the right. The strap makes an angle θ measured counterclockwise from the horizontal.
(a)
Draw a free-body diagram of the suitcase.

This answer has not been graded yet.

(b)
What angle does the strap make with the horizontal (in degrees)?
 

(c)
What is the magnitude of the normal force that the ground exerts on the suitcase (in N)?
check_circleExpert Solution
Step 1

Given values:

Weight of the suitcase, m = 15 kg

Force on the strap, F = 38.5 N

Friction force on the suitcase, fk = 20.0 N

Step 2

(a)

The free body diagram:

R
F sin
F 38.5 N
F cos A
mg
help_outline

Image Transcriptionclose

R F sin F 38.5 N F cos A mg

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Step 3

(b)

Since the bag is moving with constant velocity, the acceleration of the bag would be zero.

Applying Newton...

F cose f
ma
Plugging in the given values:
38.5x cos
20
15 x 0 0
20
cos e
38.5
20
e=cos
38.5
e=58.7
help_outline

Image Transcriptionclose

F cose f ma Plugging in the given values: 38.5x cos 20 15 x 0 0 20 cos e 38.5 20 e=cos 38.5 e=58.7

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