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A woman attached to a bungee cord jumps from a bridge that is 20 m above a river. Her height in meters above the river t seconds after the jump is y(t) = 10 (1+ e -t cost), for t2 0. a. Determine her velocity at t= 1 and t= 3. b. Use a graphing utility to determine when she is moving downward and when she is moving upward during the first 10 s. c. Use a graphing utility to estimate the maximum upward velocity. a. Her velocity at time t is given by the function v(t) = - 10 e -(cost+ sin t). Her velocity at t 1 is -5.08 (Round to two decimal places as needed.) Her velocity at t= 3 is 42. (Round to two decimal places as needed.) b. Choose the correct answer below. O A. She is moving downward for 3,14

A woman attached to a bungee cord jumps from a bridge that is 20 m above a river. Her height in meters above the river t seconds after the jump is y(t) = 10 (1+ e -t cost), for t2 0. a. Determine her velocity at t= 1 and t= 3. b. Use a graphing utility to determine when she is moving downward and when she is moving upward during the first 10 s. c. Use a graphing utility to estimate the maximum upward velocity. a. Her velocity at time t is given by the function v(t) = - 10 e -(cost+ sin t). Her velocity at t 1 is -5.08 (Round to two decimal places as needed.) Her velocity at t= 3 is 42. (Round to two decimal places as needed.) b. Choose the correct answer below. O A. She is moving downward for 3,14

College Algebra
College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter3: Functions
Section3.3: Rates Of Change And Behavior Of Graphs
Problem 46SE: Near the surface of the moon, the distance that an object falls is a function of time. It is given...
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Please help me find the upward velocity 

A woman attached to a bungee cord jumps from a bridge that is 20 m above a river. Her height in meters above the river t seconds after the jump is y(t) = 10 (1+ e- cost), for t20. a. Determine her velocity at t= 1 and t= 3. b. Use a graphing utility to determine when she is moving downward and when she is moving upward during the first 10 s. c. Use a graphing utility to estimate the maximum upward velocity. a. Her velocity at time t is given by the function v(t) = 10 e -(cost+ sin t) Her velocity att= 1 is - 5.08 (Round to two decimal places as needed.) Her velocity att= 3 is 42 (Round to two decimal places as needed.) b. Choose the correct answer below. O A. She is moving downward for 3.14 <t<6.28 and 9.42 <ts 10. She is moving upward for 0st<3.14 and 9.42 <ts 10. VB. She is moving downward for 0st<2.36 and 5.50 <t< 8.64. She is moving upward for 2.36 <t< 5.50 and 8.64 <t<10. O C. She is moving downward for 0.79 < t<3.93 and 7.07 <ts 10. She is moving upward for 0st<0.79 and 3.93 <t<7.07. O D. She is moving downward for 1.57 <t<4.71 and 7.85 <ts 10. She is moving upward for 0st<1.57 and 4.71 <t<7.85. c. The maximum upward velocity is approximately (Round to two decimal places as needed.) m/s.
Transcribed Image Text:A woman attached to a bungee cord jumps from a bridge that is 20 m above a river. Her height in meters above the river t seconds after the jump is y(t) = 10 (1+ e- cost), for t20. a. Determine her velocity at t= 1 and t= 3. b. Use a graphing utility to determine when she is moving downward and when she is moving upward during the first 10 s. c. Use a graphing utility to estimate the maximum upward velocity. a. Her velocity at time t is given by the function v(t) = 10 e -(cost+ sin t) Her velocity att= 1 is - 5.08 (Round to two decimal places as needed.) Her velocity att= 3 is 42 (Round to two decimal places as needed.) b. Choose the correct answer below. O A. She is moving downward for 3.14 <t<6.28 and 9.42 <ts 10. She is moving upward for 0st<3.14 and 9.42 <ts 10. VB. She is moving downward for 0st<2.36 and 5.50 <t< 8.64. She is moving upward for 2.36 <t< 5.50 and 8.64 <t<10. O C. She is moving downward for 0.79 < t<3.93 and 7.07 <ts 10. She is moving upward for 0st<0.79 and 3.93 <t<7.07. O D. She is moving downward for 1.57 <t<4.71 and 7.85 <ts 10. She is moving upward for 0st<1.57 and 4.71 <t<7.85. c. The maximum upward velocity is approximately (Round to two decimal places as needed.) m/s.
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