A woman exerts a horizontal force of 135 N on a box with a mass of 39.2 kg. (a)If the box doesn't move, what's the magnitude of the static friction force (in N)?  (b)What is the minimum possible value of the coefficient of static friction between the box and the floor? (Assume the box remains stationary.)

Question
Asked Nov 5, 2019
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A woman exerts a horizontal force of 135 N on a box with a mass of 39.2 kg.
 
(a)
If the box doesn't move, what's the magnitude of the static friction force (in N)?
 
 
(b)
What is the minimum possible value of the coefficient of static friction between the box and the floor? (Assume the box remains stationary.)
 
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Expert Answer

Step 1

To find :

(a)The magnitude of the static friction force (in N)

(b)The minimum possible value of the coefficient of static friction between the box and the floor
Balancing the forces, we have:
f F and N = mg
Thus
f 135N and N = 39.2x 9.81 384.552Newton
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Balancing the forces, we have: f F and N = mg Thus f 135N and N = 39.2x 9.81 384.552Newton

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Step 2

Thus,

...
Now, we also know that the maximim fricti onal force:
fm Nwhere u is the Coefficient of static fric tion between
max
the crate and floor
For minimum Coefficient of static friction
max
or fuN
f
or,u2
N
135
or,u
384.552
or,uz0.351
help_outline

Image Transcriptionclose

Now, we also know that the maximim fricti onal force: fm Nwhere u is the Coefficient of static fric tion between max the crate and floor For minimum Coefficient of static friction max or fuN f or,u2 N 135 or,u 384.552 or,uz0.351

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