A woman with normal blood clotting mates with a man who has hemophilia. Their first child is a boy who has hemophilia. Tests show that the father and son both have the same form of hemophilia, that it is X-linked recessive, and that the boy has normal genetic inheritance. You can predict that if the couple produces more children together, then the odds are that: Select one: O a. All of the children will have hemophilia. O b. Half of the boys and half of the girls will have hemophilia. O c. None of the rest of the children should have hemophilia. O d. Half of the boys and none of the girls will have hemophilia.
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- An allele responsible for Marfan syndrome Section 13.4 is inherited in an autosomal dominant pattern. What is the chance that a child will inherit the allele if one parent does not carry it and the other is heterozygous?A mother is heterozygous for the X-linked gene for colorblindness and also heterozygous for the autosomal inherited sickle cell anemia. She is married to a man who can see color normally and who is heterozygous for sickle cell trait. Using b (colorblind), B (normal color), S (normal hemoglobin), s (sickle cell), answer the following: a. What are the genotypes of the parents? b: What is the probability of having a child who is both color blind and has sickle cell anemia?A woman homozygous for normal height, with freckles, almond-shaped eyes, small nose, and Type A blood, has a Type O mother with no freckles and a type AB father with round eyes. She is engaged to a man with achondroplasia, round eyes and medium sized nose. Unlike his father, hismother is of normal height. Both his parents have Type O blood but nobody from both sides of his family has or had freckles. a. Write the COMPLETE genotypes of the man and the woman. Clearly indicate which genotype belongs to whom. b. Based on their genotypes, what is the probability that they will have: b.1 a child with Achondroplasia? b.2 a child of normal height? b.3 a child with type AB blood? b.4 a daughter with round eyes, freckles, and medium sized nose? b.5 a son with almond eyes, no freckles, and small nose?b.6 a daughter with same genotype as the woman? b.7 a son with same genotype as the man?
- A form of hemophilia is caused by a sex-linked (X-linked) recessive gene. A phenotypically normal woman whose father had hemophilia marries a man who suffers with hemophilia. What is the probability that their first daughter will have hemophilia?A form of hemophilia is caused by a sex-linked (X-linked) recessive gene. A phenotypically normal woman whose father had hemophilia marries a phenotypically normal man with no family history of hemophilia. What is the probability that their first son will have hemophilia? 1/4 1 3/4 0 1/2A man with X-linked color blindness marries a woman with no history of color blindness in her family. The daughter of this couple marries a normal man, and their daughter also marries a normal man. What is the chance that this last couple will have a child with color blindness? If this couple has already had a child with color blindness, what is the chance that their next child will be color blind?
- Hemophilia is an X-linked disorder that affects the body’s ability to create blood clots. The allele for normal blood clotting, XH, is dominant over the allele for hemophilia, Xh. An unaffected daughter from the above cross married a man who does not have hemophilia. Determine the probability of their offspring being A daughter with hemophilia A daughter without hemophilia A son with hemophilia A son without hemophilia Express your answer as a phenotypic ratio. Number: Answer Answer Answer Answer Phenotype: Affected female Unaffected female Affected male Unaffected maleFor the Y-linked gene, use T for hypertrichosis. For X-linked genes, use the letters H for blood trait and E for eye trait. Krisha, a carrier of the genes for hemophilia and colorblindness, is married to Kyle who is color blind, having normal red blood cells. Veronica (Krisha & Kyle's daughter), turned out to be a carrier for both genes. Julian has hypertrichosis and is married to Josie. Both do not exhibit any allele for color blindness and never had any history for hemophilia. Bernard (Julian & Josie's son) will be married to Veronica. What are the complete genotypes of the following persons: a. Krisha b. Kyle c. Veronica d. Julian e. Josie f. Bernard g. Josie & Bernard's babyHemophilia is due to a sex-linked gene. It is recessive and found on the X chromosome. A woman who is a carrier for hemophilia marries a normal man. What will be the possible phenotypes of their children? (use the letter “H”)
- A woman who has blood type A positive has a daughter who is type O positive and a son who is type B negative. Rh positive is a trait that shows simple dominance over Rh negative and is designated by the alleles R and r, respectively. A third gene for the MN blood group has co dominant alleles M and N. If both children are of blood type M in addition to their ABO blood type, list all of the possible parental phenotypes for the ABO, MN and Rh traits.Hemophilia is an X-linked disease associated with the inability to produce specific proteins in the blood-clotting pathway. Shown above is a family pedigree tree in which family members afflicted with the disease are shown with filled-in squares (male) or circles (females). A couple is trying to determine the likelihood of passing on the disease to their future children (represented by the ? symbol above) because the hemophilia runs in the woman’s family 4.Assuming that the woman in the couple is a carrier, what is the probability that the couple’s first son will have hemophilia?A woman with type A blood and a man with type B blood have a child with type O blood. Can this man be the father? Choose the best answer below: a No, he can not be the father because A and B are codominant b No, he cannot be the father because type O blood is recessive c Yes, he can be the father if both parents are carriers for type O blood d Yes, he can be the father if the blood type is X-linked on the maternal side