a) You have 150.0 mL of a 0.821 M solution of Ce(NO₃)₄. What mass (in grams) of Ce(NO₃)₄ would be required to make the solution? b) You have 150.0 mL of a 0.821 M solution of Ce(NO₃)₄. What is the concentration of the nitrate ions in the solution? c) You have 150.0 mL of a 0.821 M solution of Ce(NO₃)₄. If the original solution was diluted to 350.0 mL, what would be the new concentration of the Ce(NO₃)₄ in the solution?
a) You have 150.0 mL of a 0.821 M solution of Ce(NO₃)₄. What mass (in grams) of Ce(NO₃)₄ would be required to make the solution? b) You have 150.0 mL of a 0.821 M solution of Ce(NO₃)₄. What is the concentration of the nitrate ions in the solution? c) You have 150.0 mL of a 0.821 M solution of Ce(NO₃)₄. If the original solution was diluted to 350.0 mL, what would be the new concentration of the Ce(NO₃)₄ in the solution?
General Chemistry - Standalone book (MindTap Course List)
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ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
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Chapter4: Chemical Reactions
Section: Chapter Questions
Problem 4.93QP: A solution of hydrogen peroxide, H2O2, is titrated with a solution of potassium permanganate, KMnO4....
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a) You have 150.0 mL of a 0.821 M solution of Ce(NO₃)₄. What mass (in grams) of Ce(NO₃)₄ would be required to make the solution?
b) You have 150.0 mL of a 0.821 M solution of Ce(NO₃)₄. What is the concentration of the nitrate ions in the solution?
c) You have 150.0 mL of a 0.821 M solution of Ce(NO₃)₄. If the original solution was diluted to 350.0 mL, what would be the new concentration of the Ce(NO₃)₄ in the solution?
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