a. 9.4 m/s b.8.0 m/s 17S d. 5.2 m/s 11. A ball is released from h and goes around a loop-the-loop. If the track is friction less and h = 3.5R, what is the speed at the top of the loop? (Use energy conservation) a. (3gR)12 b. (5gR)2 c.(7gR)12 d. (9gR)12 h-3-5R TREL.8

a. 9.4 m/s b.8.0 m/s 17S d. 5.2 m/s 11. A ball is released from h and goes around a loop-the-loop. If the track is friction less and h = 3.5R, what is the speed at the top of the loop? (Use energy conservation) a. (3gR)12 b. (5gR)2 c.(7gR)12 d. (9gR)12 h-3-5R TREL.8

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter5: Energy

Section: Chapter Questions

Problem 44P: A 25.0-kg child on a 2.00-m-long swing is released from rest when the ropes of the swing make an...

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Question

a. 9.4 m/s
b.8.0 m/s
17S
d. 5.2 m/s
11. A ball is released from h and goes around a loop-the-loop. If the track is friction less and h = 3.5R, what is
the speed at the top of the loop? (Use energy conservation)
a. (3gR)12
b. (5gR)2
c.(7gR)12
d. (9gR)12
h-3-5R
TREL.8

Expert Solution

Step 1

Given values:

h = 3.5 R

Initial speed of the ball, u = 0 m/s

Let the speed at the top of the loop be v

Mechanical energy = Kinetic energy + Potential energy.

Step 2

From the conservation of energy:

Mechanical energy at height h (releasing point) = mechanical energy at the top of the loop

Physics homework question answer, Step 2, Image 1

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