A. By default, the positions are on x1 1.00m and x2 +1.00m. Adjust the elasticity to 100%. Then set the values of mass and velocity based on the given on the table below. Complete the table by writing the values for the final velocities and final momentum. Mass (kg) Initial Velocities Momentum (kg m/s) Initial Total Initial Final Velocities Momentum (m/s) Final Total Final Trials (m/s) Momentum (kg-m/s) Momentum (kg-m/s) (kg m/s) Trial 1 mi= 0.50 Vi= 1.25 pi= vi= pi p= p= my= 1.00 V= -1.00 V2= p2 mi= 1.35 Vi= 0.80 pi= Vi= Trial 2 p= p= m2= 0.90 V2= -1.60 V2= p2 =
A. By default, the positions are on x1 1.00m and x2 +1.00m. Adjust the elasticity to 100%. Then set the values of mass and velocity based on the given on the table below. Complete the table by writing the values for the final velocities and final momentum. Mass (kg) Initial Velocities Momentum (kg m/s) Initial Total Initial Final Velocities Momentum (m/s) Final Total Final Trials (m/s) Momentum (kg-m/s) Momentum (kg-m/s) (kg m/s) Trial 1 mi= 0.50 Vi= 1.25 pi= vi= pi p= p= my= 1.00 V= -1.00 V2= p2 mi= 1.35 Vi= 0.80 pi= Vi= Trial 2 p= p= m2= 0.90 V2= -1.60 V2= p2 =
International Edition---engineering Mechanics: Statics, 4th Edition
4th Edition
ISBN:9781305501607
Author:Andrew Pytel And Jaan Kiusalaas
Publisher:Andrew Pytel And Jaan Kiusalaas
Chapter4: Coplanar Equilibrium Analysis
Section: Chapter Questions
Problem 4.9P: The high-pressure water cock is rigidly attached to the support at D. Neglecting the weights of the...
Related questions
Question
pls. see the attached photo, please help me huhu
Transcribed Image Text:A. By default, the positions are on x1 = - 1.00m and x2 = +1.00m. Adjust the elasticity to 100%.
Then set the values of mass and velocity based on the given on the table below. Complete the
table by writing the values for the final velocities and final momentum.
Final
Velocities
Mass
Initial
Initial
Total
Final
Total
(kg)
Velocities
Momentum
Initial
Momentum
Final
Trials
(m/s)
(kg-m/s)
Momentum
(m/s)
(kg m/s)
Momentum
(kg m/s)
(kg m/s)
mi= 0.50
Vi= 1.25
pi=
Vi =
pi =
Trial 1
p=
p=
m= 1.00
V2= -1.00
p2=
V2 =
P2 =
Vi =
vz=
pi =
p2 =
mi= 1.35
Vi= 0.80
pi=
Trial 2
p=
p=
m2= 0.90
V2= -1.60
p2=
Transcribed Image Text:By default, the positions are on x1 = - 1.00m and x2=+1.00m.. Adjust the elasticity to 0%. Then
set the values of mass and velocity based on the given on the table below. Complete the table by
writing the values for the final velocities and final momentum.
Mass
Initial
Initial
Total
Final
Final
Total
Trials
(kg)
Velocities
Momentum
Initial
Velocities
Momentum
Final
(m/s)
(kg m/s)
Momentum
(m/s)
(kg-m/s)
Momentum
(kg-m/s)
(kg-m/s)
Trial 1
mi= 0.50
Vi= 1.25
pi=
Vị =
Pi =
m2= 1.00
V2= -1.00
p=
p=
p2=
V2
p2 =
mi= 1.35
Vi= 0.80
VI =
V2 =
Pi=
Pi =
p2 =
Trial 2
m2= 0.90
V2= -1.60
p=
p3=
p2=
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Recommended textbooks for you
International Edition---engineering Mechanics: St…
Mechanical Engineering
ISBN:
9781305501607
Author:
Andrew Pytel And Jaan Kiusalaas
Publisher:
CENGAGE L
International Edition---engineering Mechanics: St…
Mechanical Engineering
ISBN:
9781305501607
Author:
Andrew Pytel And Jaan Kiusalaas
Publisher:
CENGAGE L