a. Find the best point estimate of the mean. b. Find the 95% confidence interval of the mean score for all footballers. Find the 95% confidence interval of the mean score if a sample of 60 footballers is used instead of a sample of 35. C.

Q: Use the Student's t distribution to find t, for a 0.95 confidence level when the sample is 27.

A: sample size=n=27 Degree of Freedom=n-1=27-1 =26 Confidence level is 0.95 Therefore the Level of…

Q: If X = 117, o=24, and n = 30, construct a 99% confidence interval estimate of the population mean, µ

A: It is given that Sample size n = 30 Sample mean = 117 Population SD = 24

Q: The figure to the right shows the results of a survey in which 1011 adults from Country​ A, 1003…

A: Note- As per our policy we can answer only the first 3 sub-parts of a question. If you want…

Q: If X = 114, α= 20, and n = 33, construct a 99% confidence interval estimate for the population mean,…

A: Given data:  Sample Mean = 114 Population standard deviation = 20 Sample size = 33 Confidence level…

Q: A university dean is interested in determining the proportion of students who receive some sort of…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: find the margin of error for a sample mean, given n=16, s=4, Xbar=17. for a 95% confidence interval.

A: The margin of error for sample mean is given by,

Q: If n = 330 and X = 264, construct a 95% confidence interval for the population proportion, p.

A:

Q: Out of 156 Nielsen families surveyed about their viewing habits, 43 felt that television was too…

A: We have given that,  Favorable cases (X) = 43 and sample size (N) = 156  Then,  We will find the 99%…

Q: For the provided sample​ mean, sample​ size, and population standard​ deviation, complete parts​ (a)…

A: Given data,n=100x=22σ=3z-value at 95% confidence is Zc=1.96

Q: 1. Consider the data set below, which gives a sample of fifteen students randomly selected and asked…

A:

Q: Construct the 94% confidence interval estimate of the population proportion ? if the sample size is…

A:

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: Given Information n =87 x =48

Q: Use the given confidence interval to find the margin of error and the sample mean. (15.3,22.3)

A: We have to find sample mean and margin of error..

Q: Construct the 95% confidence interval estimate of the population proportion ? if the sample size is…

A: Given Data Sample Size, n = 400 Number of successes, x = 52.0 confidence level,c=…

Q: Use the given confidence interval to find the margin of error and the sample mean . (12.9, 20.1)

A: See the handwritten solution

Q: Set 1 Set 2 Set 3 121.771 121.784 121.752 121.787 121.758 121.784 121.765 121.803 121.765 121.781…

A: In Independent sample t-test we are comparing the means of two independent groups. Let μ1 be the…

Q: 11. A television station surveys 200 customers and finds that 23% of customers watch the evening…

A: Margin of error = z*√(pq/n) Where z= z value            n=no of customer            q=1-p…

Q: If a student provided 90% confidence intervals in all ten questions, how many points would we expect…

A: In the given analysis, we have 10 questions and their correct answers. 10 sample responses from 10…

Q: Do People Think the Sun Goes around the Earth? In the 2018 General Social Survey, people were asked…

A: According to our policy we can answer only first three part for remaining please repost the…

Q: Given the following confidence interval for a population mean, compute the margin of error, E.…

A: A confidence interval of population mean, µ, in terms of sample mean and margin of error, can be…

Q: If n=200 and ˆpp^ (p-hat) =0.39, find the margin of error at a 99% confidence level

A: Find z-critical value:…

Q: If n=150 and ˆpp^ (p-hat) =0.25, find the margin of error at a 90% confidence level

A: n = 150p^ = 0.2590% confidence level

Q: If X=72​, σ=13​, and n=66​, construct a 95​% confidence interval estimate of the population​…

A:

Q: Use the given degree of confidence and sample data to construct a confidence interval for the…

A: It is given that n=195 and x=162. The sample proportion is 162/195 = 0.8308 The sample size is 195…

Q: (b) Use a 99% confidence interval to estimate the mean percent change in the population. FILE O…

A: (b) The mean percent is, x¯=∑xn=-4.7-2.5-4.9-2.7+⋯-5.147=-168.647=-3.5872 The mean percent is…

Q: Given the following confidence interval for a population mean, compute the margin of error, E.…

A: According to the provided information, 10.18<μ<11.90

Q: b. Calculate a 95% confidence interval for the proportion of the population who have been told they…

A: b. A sample 1,414 adults are taken for a survey to ask the question that "Have you ever been told…

Q: Given the information: the sampled population is normally distributed, X– = 36.5, σ = 3, and n = 20.…

A: Given that

Q: If (220 ,230) is a confidence interval for the population mean p, then the point estimator in this…

A:

Q: Which of the common confidence levels (90%, 95%, or 99%) would you prefer to use if you wanted to…

A: Introduction: The “smallest” confidence interval implies the confidence interval with the shortest…

Q: a. Given that Emily used a coin toss to select either her right hand or her left​ hand, what…

A: a. Given that Emily used a coin toss to select either her right hand or her left​ hand, what…

Q: What is the critical t-value for finding a 95 percent confidence interval estimate from a sample of…

A: Given: Sample size (n)=18 Confidence level = 95% Level of significance = 1-confidence level = 1-0.95…

Q: The table shows the results of a survey in which separate samples of 400 adults each from the East,…

A:

Q: Suppose a 90 percent confidence interval to estimate a population proportion was calculated from a…

A: Solution: From the given information, the sample proportion is 18% and a margin of error is 4…

Q: The figure to the right shows the results of a survey in which 999 adults from Country A, 1002…

A:

Q: If X=68​, σ=14​, and n=66​, construct a 95​% confidence interval estimate of the population​ mean, μ

A:

Q: If X-bar = 125, σ = 24, and n = 36, construct a 99% confidence interval estimate for the population…

A: Given: X-bar = 125, σ = 24, n = 36.

Q: The manager of a car company will select a random sample of its customers to create a 90 percent…

A: From the provided information, Confidence level = 90% Margin of error = 0.06

Q: (d) Use the combined data of 80 students, construct a 95% confidence interval estimate of the…

A: Given that  Total students=n=40+40=80 Number of pass students=X=28+32=60

Q: Given below are the sodium contents in milligrams for seven brands of hot dogs rated as “very good”…

A:

Q: how many samples out of 100 would you expect to not include the true population mean within their…

A: here given ,  confidence level =  90%  sample size  = 100

Q: c) i: Calculate the average and median to the results. ii: Find a 95% confidence interval for µ.

A: S.no. x (x-xbar)^2 1 11.79 0.03092 2 11.82 0.02127 3 11.87 0.00918 4 11.92 0.00210 5 11.93…

Q: 1. Consider the data set below, which gives a sample of fifteen students randomly selected and asked…

A: Note: "Since you have posted a question with multiple sub -parts, we will solve first three sub…

Q: Use the given confidence interval to find the margin of error and the sample mean. (13.5,21.9)

A: Given confidence interval (13.5, 21.9)

Q: If X=80​, σ=11​,and n=62​,construct a 95​% confidence interval estimate of the population​ mean, μ.…

A: Given,sample size(n)=62sample mean(x¯)=80standard deviation(σ)=11α=1-0.95=0.05α2=0.025Z0.025=1.96…

Q: The figure to the right shows the results of a survey in which 1003 adults from Country A, 1024…

A: Given information For country A p-hat = 0.35 n = 1003

Q: 26.4, 226.9, 227.1, and 228.6.  Student B:  229.5, 226.1, 230.7, 223.8, and 227.5

A: For student A: Sample size, n=5 228.3, 226.4, 226.9, 227.1, 228.6…

Q: If n=420 and ˆpp^ (p-hat) =0.19, find the margin of error at a 95% confidence level

A:

Q: If n=17, (x-bar)=44, and s=8, find the margin of error at a 95% confidence level

A: The sample mean is 44 and standard deviation is 8.