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a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval. b. Use a graphing utility to find all the solutions to the equation on the given interval. c. Illustrate your answers with an appropriate graph. 2x° +x-1 = 0; (0,1) Why can the Intermediate Value Theorem be used to show that the equation has a solution on (0,1)? A. It can be used because f(x) = 2x° + x- 1 is continuous on [0,1] and 0 is between f(0) and f(1). O B. It can be used because f(x) = 2x° + x - 1 is defined on (0,1) and f(0) < f(1) < 0. O C. It can be used because f(x) = 2x° + x - 1 is defined on (0,1) and 0< f(0) < f(1). O D. It can be used because f(x) = 2x° +x - 1 is continuous on [0,1] and the function is defined at x = 0 and x = 1. b. There is/are a solution(s) to the equation in (0,1) at x = 0.590. (Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as needed.) c. Choose the correct graph below. The window setting is for each graph is [- 1,2,1] by [- 10,10,1]. A. O B. C. O D.

a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval. b. Use a graphing utility to find all the solutions to the equation on the given interval. c. Illustrate your answers with an appropriate graph. 2x° +x-1 = 0; (0,1) Why can the Intermediate Value Theorem be used to show that the equation has a solution on (0,1)? A. It can be used because f(x) = 2x° + x- 1 is continuous on [0,1] and 0 is between f(0) and f(1). O B. It can be used because f(x) = 2x° + x - 1 is defined on (0,1) and f(0) < f(1) < 0. O C. It can be used because f(x) = 2x° + x - 1 is defined on (0,1) and 0< f(0) < f(1). O D. It can be used because f(x) = 2x° +x - 1 is continuous on [0,1] and the function is defined at x = 0 and x = 1. b. There is/are a solution(s) to the equation in (0,1) at x = 0.590. (Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as needed.) c. Choose the correct graph below. The window setting is for each graph is [- 1,2,1] by [- 10,10,1]. A. O B. C. O D.

Algebra for College Students
Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.2: Parabolas
Problem 58PS
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All or majority of the answers are given. Please explain step by step with detail on how the answer came to be. Please do not just list the math steps, explain with words on the steps take or what you did in each step please.

a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval. b. Use a graphing utility to find all the solutions to the equation on the given interval. c. Illustrate your answers with an appropriate graph. 2x° + x- 1 = 0; (0,1) Why can the Intermediate Value Theorem be used to show that the equation has a solution on (0,1)? It can be used because f(x) = 2x° + x- 1 is continuous [0,1] and 0 is between f(0) and f(1). В. It can be used because f(x) = 2x + x-1 is defined on (0,1) and f(0) < f(1) < 0. It can be used because f(x) = 2x° + x - 1 is defined on (0,1) and 0< f(0) < f(1). O D. It can be used because f(x) = 2x + x - 1 is continuous [0,1] and the function is defined at x=0 and x = 1. b. There is/are a solution(s) to the equation in (0,1) at x 0.590 (Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as needed.) c. Choose the correct graph below. The window setting is for each graph is [- 1,2,1] by [- 10,10,1]. OB. OC. O D. Question is complete. Tap on the red indicators to see incorrect answers. O 包
Transcribed Image Text:a. Use the Intermediate Value Theorem to show that the following equation has a solution on the given interval. b. Use a graphing utility to find all the solutions to the equation on the given interval. c. Illustrate your answers with an appropriate graph. 2x° + x- 1 = 0; (0,1) Why can the Intermediate Value Theorem be used to show that the equation has a solution on (0,1)? It can be used because f(x) = 2x° + x- 1 is continuous [0,1] and 0 is between f(0) and f(1). В. It can be used because f(x) = 2x + x-1 is defined on (0,1) and f(0) < f(1) < 0. It can be used because f(x) = 2x° + x - 1 is defined on (0,1) and 0< f(0) < f(1). O D. It can be used because f(x) = 2x + x - 1 is continuous [0,1] and the function is defined at x=0 and x = 1. b. There is/are a solution(s) to the equation in (0,1) at x 0.590 (Type an integer or decimal rounded to three decimal places as needed. Use a comma to separate answers as needed.) c. Choose the correct graph below. The window setting is for each graph is [- 1,2,1] by [- 10,10,1]. OB. OC. O D. Question is complete. Tap on the red indicators to see incorrect answers. O 包
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