A. y = (x – 2)² +2 B. y = -(x – 2)² + 2 C. y = (x – 2)2 + 2 D. y = -(x – 2)² – 2 10 12

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.4: Definition Of Function
Problem 51E
icon
Related questions
icon
Concept explainers
Question
100%

For numbers 6-8, identify the quadratic function given in the graph. 

• Follow This One!
Study the graph of the quadratic function below. Determine the equation
given in the graph by following the steps below.
1. Identify the vertex (h, k)
2. Identify the coordinates of
any point on the parabola.
3. Substitute the vertex (h, k)
and coordinates of any
point (x, y)into the vertex
form y = a(x – h)² + k.
4. Get the value of a.
5. Write the equation of the
quadratic function.
Example
• Try to Understand!
When the vertex and any point on the parabola are clearly seen, the
equation of the quadratic function can be determined by using the form of a
quadratic function y = a(x – h)2 + k.
Do the "Follow This One!" activity above. The vertex of the graph of
the quadratic function is (4, -2). The graph passes through the point (2,0). By
11
replacing x and y with 2 and 0, respectively, and h and k with 4 and -2
respectively, we have
y = a(x – h)² + k
(0) = a(2 – 4)2 + (-2) the x-intercept
0 = 4a – 2
ta
Substitute the vertex and
Substitute the vertex, h=4, k=.
2 and the value of a= to y =
Simplify
Divide both sides
a(x – h)² + k form the
required quadratic function
y = a(x – h)² + k
by 4
1
y =; (x – 4)2 – 2
Thus, the quadratic equation is y = (x – 4)² – 2.
Transcribed Image Text:• Follow This One! Study the graph of the quadratic function below. Determine the equation given in the graph by following the steps below. 1. Identify the vertex (h, k) 2. Identify the coordinates of any point on the parabola. 3. Substitute the vertex (h, k) and coordinates of any point (x, y)into the vertex form y = a(x – h)² + k. 4. Get the value of a. 5. Write the equation of the quadratic function. Example • Try to Understand! When the vertex and any point on the parabola are clearly seen, the equation of the quadratic function can be determined by using the form of a quadratic function y = a(x – h)2 + k. Do the "Follow This One!" activity above. The vertex of the graph of the quadratic function is (4, -2). The graph passes through the point (2,0). By 11 replacing x and y with 2 and 0, respectively, and h and k with 4 and -2 respectively, we have y = a(x – h)² + k (0) = a(2 – 4)2 + (-2) the x-intercept 0 = 4a – 2 ta Substitute the vertex and Substitute the vertex, h=4, k=. 2 and the value of a= to y = Simplify Divide both sides a(x – h)² + k form the required quadratic function y = a(x – h)² + k by 4 1 y =; (x – 4)2 – 2 Thus, the quadratic equation is y = (x – 4)² – 2.
A. y = (x – 2)² + 2
B. y = -(x – 2)² + 2
C. y = (x – 2)² + 2
D. y = -(x – 2)² – 2
6.
2
-4
-2
10
-2
12
A. y = (x – 2)²
B. y = -(x – 2)²
C. y = (x + 2)²
D. y = -(x + 2)2
7.
A. y = -4(x + 2)² + 1
В. у %3D -4 (х — 2)2 - 1
C. y = 4(x – 2)² + 1
D. y = 4(x – 2)² – 1
8.
Transcribed Image Text:A. y = (x – 2)² + 2 B. y = -(x – 2)² + 2 C. y = (x – 2)² + 2 D. y = -(x – 2)² – 2 6. 2 -4 -2 10 -2 12 A. y = (x – 2)² B. y = -(x – 2)² C. y = (x + 2)² D. y = -(x + 2)2 7. A. y = -4(x + 2)² + 1 В. у %3D -4 (х — 2)2 - 1 C. y = 4(x – 2)² + 1 D. y = 4(x – 2)² – 1 8.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps

Blurred answer
Knowledge Booster
Application of Differentiation
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
Algebra and Trigonometry (MindTap Course List)
Algebra and Trigonometry (MindTap Course List)
Algebra
ISBN:
9781305071742
Author:
James Stewart, Lothar Redlin, Saleem Watson
Publisher:
Cengage Learning
Elements Of Modern Algebra
Elements Of Modern Algebra
Algebra
ISBN:
9781285463230
Author:
Gilbert, Linda, Jimmie
Publisher:
Cengage Learning,
Elementary Geometry for College Students
Elementary Geometry for College Students
Geometry
ISBN:
9781285195698
Author:
Daniel C. Alexander, Geralyn M. Koeberlein
Publisher:
Cengage Learning