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A. y =(x- 2) B. y = -x- 2) C. y =(x+ 2)? D. y = -x + 2)? A. y = -4(x + 2)² +1 B. y = -4(x – 2)² – 1 C. y = 4(x – 2)² +1 D. y = 4(x – 2)² - 1

A. y =(x- 2) B. y = -x- 2) C. y =(x+ 2)? D. y = -x + 2)? A. y = -4(x + 2)² +1 B. y = -4(x – 2)² – 1 C. y = 4(x – 2)² +1 D. y = 4(x – 2)² - 1

Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter6: Fractions
Section6.7: Polynomial Long Division
Problem 21E
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What are the quadratic functions? I had troubles number 7 and 8

• Follow This One! Study the graph of the quadratic function below. Determine the equation given in the graph by following the steps below. 1. Identify the vertex (h, k) 2. Identify the coordinates of any point on the parabola. 3. Substitute the vertex (h, k) and coordinates of any point (x, y)into the vertex form y = a(x – h)? + k. 4. Get the value of a. 5. Write the equation of the quadratic function. * Try to Understand! When the vertex and any point on the parabola are clearly seen, the equation of the quadratic function can be determined by using the form of a quadratic function y = a(x – h)² + k. Do the "Follow This One!"" activity above. The vertex of the graph of the quadratic function is (4, –2). The graph passes through the point (2,0). By 11 Example replacing x and y with 2 and 0, respectively, and h and k with 4 and -2 respectively, we have y = a(x – h)² + k (0) = a(2 – 4)² + (-2) the x-intercept 0 = 4a – 2 ta Substitute the vertex and Substitute the vertex, h=4, k=- 2 and the value of a to y = a(x – h)? + k form the required quadratic function y = a(x – h)² +k y =5(x- 4)² – 2 Simplify Divide both sides by 4 a =7 Thus, the quadratic equation is y =(x- 4)² – 2. Note: To determine a quadratic function given its graph, you need to have the vertex any point of the graph.
Transcribed Image Text:• Follow This One! Study the graph of the quadratic function below. Determine the equation given in the graph by following the steps below. 1. Identify the vertex (h, k) 2. Identify the coordinates of any point on the parabola. 3. Substitute the vertex (h, k) and coordinates of any point (x, y)into the vertex form y = a(x – h)? + k. 4. Get the value of a. 5. Write the equation of the quadratic function. * Try to Understand! When the vertex and any point on the parabola are clearly seen, the equation of the quadratic function can be determined by using the form of a quadratic function y = a(x – h)² + k. Do the "Follow This One!"" activity above. The vertex of the graph of the quadratic function is (4, –2). The graph passes through the point (2,0). By 11 Example replacing x and y with 2 and 0, respectively, and h and k with 4 and -2 respectively, we have y = a(x – h)² + k (0) = a(2 – 4)² + (-2) the x-intercept 0 = 4a – 2 ta Substitute the vertex and Substitute the vertex, h=4, k=- 2 and the value of a to y = a(x – h)? + k form the required quadratic function y = a(x – h)² +k y =5(x- 4)² – 2 Simplify Divide both sides by 4 a =7 Thus, the quadratic equation is y =(x- 4)² – 2. Note: To determine a quadratic function given its graph, you need to have the vertex any point of the graph.
A. y = (x– 2)? B. y = -(x- 2)? C. y =(x + 2)2 D. y = -(x + 2)2 7. A. y = -4(x + 2)² +1 B. y = -4(x – 2)² – 1 C. y = 4(x – 2)² +1 D. y = 4(x – 2)² –1 8. -1
Transcribed Image Text:A. y = (x– 2)? B. y = -(x- 2)? C. y =(x + 2)2 D. y = -(x + 2)2 7. A. y = -4(x + 2)² +1 B. y = -4(x – 2)² – 1 C. y = 4(x – 2)² +1 D. y = 4(x – 2)² –1 8. -1
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