Question

Asked Nov 29, 2019

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A 0.0230 kg bullet moving horizontally at 500 m/s embeds itself into an initially stationary 0.500 kg block.(a) What is their velocity just after the collision?

_________ m/s

(b) The bullet-embedded block slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction. Now what is its velocity?

_________ m/s

(c) The bullet-embedded block now strikes and sticks to a stationary 2.00 kg block. How far does this combination travel before stopping?

_________ m

Step 1

**Given:**

Mass of the bullet = 0.0230 kg

Speed of the bullet = 500 m/s

Step 2

Calculating the final velocity of the bullet-embedded block just after collision:

Step 3

Calculating the velocity of the bullet-emb...

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