A 1020 kg car is pulling a 285 kg trailer. Together, the car and trailer have an acceleration of 2.01 m/s2 in the forward direction. Neglecting frictional forces on the trailer, determine the following. (Indicate the direction with the sign of your answer. Take the forward direction to be positive.) (a) the net force on the

A 1020 kg car is pulling a 285 kg trailer. Together, the car and trailer have an acceleration of 2.01 m/s2 in the forward direction. Neglecting frictional forces on the trailer, determine the following. (Indicate the direction with the sign of your answer. Take the forward direction to be positive.) (a) the net force on the

Name: A 1020 kg car is pulling a 285 kg trailer. Together, the car and trail
Uploaded: 2024-03-20T06:57:57.000Z
Channel: Bartleby
Description: A 1020 kg car is pulling a 285 kg trailer. Together, the car and trailer have an acceleration of 2.01 m/s2 in the forward direction. Neglecting frictional forces on the trailer, determine the following. (Indicate the direction with the sign of your a

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter4: The Laws Of Motion

Section: Chapter Questions

Problem 1P: A force F applied to an object of mass m1 produces an acceleration of 3.00 m/s2. The same force...

See similar textbooks

Similar questions

In the figure, a slab of mass m1 = 40 kg rests on a frictionless floor, and a block of mass m2 = 10 kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.40. A horizontal force F→ of magnitude 104 N begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?
a slab of mass m1 40 kg rests on a frictionless floor, and a block of mass m2 10 kg rests on top of the slab. Between block and slab, the coefficient of static friction is 0.60, and the coefficient of kinetic friction is 0.40.A horizontal force of magnitude 100 N begins to pull directly on the block, as shown. In unit-vector notation, what are the resulting accelerations of (a) the block and (b) the slab?
A 900 kg car is pulling a 275 kg trailer. Together, the car and trailer have an acceleration of 2.21 m/s2 in the forward direction. Neglecting frictional forces on the trailer, determine the following. (Indicate the direction with the sign of your answer. Take the forward direction to be positive.) (c) the force exerted by the trailer on the car (d) the resultant force exerted by the car on the road magnitude N direction ° (below the horizontal from the forward direction)
A 900 kg car is pulling a 275 kg trailer. Together, the car and trailer have an acceleration of 2.21 m/s2 in the forward direction. Neglecting frictional forces on the trailer, determine the following. (Indicate the direction with the sign of your answer. Take the forward direction to be positive.)(c) the force exerted by the trailer on the car(d) the resultant force exerted by the car on the road magnitude N direction ° (below the horizontal from the forward direction)
A 960 kg car is pulling a 300 kg trailer. Together, the car and trailer have an acceleration of 2.09 m/s2 in the forward direction. Neglecting frictional forces on the trailer, determine the following. (Indicate the direction with the sign of your answer. Take the forward direction to be positive.) (a) the net force on the car 2006 N(b) the net force on the trailer 627 N(c) the force exerted by the trailer on the car -627 N(d) the resultant force exerted by the car on the road magnitude _______N direction _______° (below the horizontal from the forward direction) HELP ASAP, I NEED PORTION D ANSWER. FYI MAGNITUDE IS NOT 9408 AND DIRECTION IS NOT 90.
A block with mass m1 = 8.6 kg rests on the surface of a horizontal table which has a coefficient of kinetic friction of μk = 0.74. A second block with a mass m2 = 10.2 kg is connected to the first by an ideal string passing over an ideal pulley such that the second block is suspended vertically. The second block is released from rest, and motion occurs. 1. Using the variable T to represent tension, write an expression for the sum of the forces in the y-direction, ΣFy, for block 2. 2. Using the variable T to represent tension, write an expression for the sum of the forces in the x-direction, ΣFx for block 1. 3. Block 1 accelerates along the tabletop, in the horizontal direction, while block 2 moves vertically. With the coordinate system provided in the drawing, we may write a1=a1i and a2=a2y. Write an expression that relates the vertical component of the acceleration of block 2 to the horizontal component of the acceleration of block 1. 4. Write an expression using the variables…
Make a line graph of the acceleration (Y axis) vs. different amount of forces units (X axis) of table 1 and make a deduction regarding the relationship of the acceleration of an object with respect to the force acting on it. Table 1: Y-Axis (acceleration) X-axis (amount of forces) 0.55 m/s^2 1 unit 1.0875 m/s^2 2 units 1.6125 m/s^2 3 units 2.1125 m/s^2 4 units
A block of mass m₁ = 3.70 kg on a frictionless plane inclined at an angle of 30.0° is connected by a cord over a massless, frictionless pulley to a second block of mass m₂ = 2.30 kg. What are (a) the magnitude of the acceleration of each block, (b) the direction of the acceleration of the hanging block, and (c) the tension in the cord? Please show a simple diagram or illustration for this problem. Thank you!
According to a simplified model of a mammalian heart, at each pulse, approximately 20 g of blood is accelerated from 0.26 m/s to 0.35 m/s during a period of 0.10 s. What is the magnitude of the force exerted by the heart muscle? Express your answer to two significant figures and include the appropriate units. F= ______ units I got 0.02N but it is wrong.
A force acts on a car of mass m so that the speed v of the car increases with position x as v = kx2 , where k is constant and all quantities are in SI units. Find the force acting on the car as a function of position.
A cart of mass 8.0kg was moved by applying two constant forces. Force 1 is 28.0N at 42.0 degrees, and Force 2 is 13.0N at 110 degrees. Initially, the cart has a velocity of (3.50i + 2.20j)m/s. a. Express the two forces in unit-vector notation.b. Find the total force exerted on the cart.c. Find the angle at which the total force is applied.d. What is the acceleration of the cart?e. What is the cart's velocity after 5.0s?f. What is the position of the cart after 5.0s?g. What is the angle of the position after 5.0s?h. What is the total work done by the two applied forces?
A block with mass m1 = 9.2 kg rests on the surface of a horizontal table which has a coefficient of kinetic friction of μk = 0.58. A second block with a mass m2 = 10.8 kg is connected to the first by an ideal string passing over an ideal pulley such that the second block is suspended vertically. The second block is released from rest, and motion occurs. Using the variable T to represent tension, write an expression for the sum of the forces in the y-direction, ΣFy, for block 2. Using the variable T to represent tension, write an expression for the sum of the forces in the x-direction, ΣFx for block 1. Block 1 accelerates along the tabletop, in the horizontal direction, while block 2 moves vertically. With the coordinate system provided in the drawing, we may write a⃗ 1=a1i^a→1=a1i^ and a⃗ 2=a2y^a→2=a2y^. Write an expression that relates the vertical component of the acceleration of block 2 to the horizontal component of the acceleration of block 1. Write an expression using the…