A 11 kg crate is placed on a horizontal conveyor belt. The materials are such that μs = 0.46  and μk = 0.20. A)What is the maximum acceleration the belt can have without the crate slipping? a_max=______ B)If acceleration of the belt exceeds the value determined in part A, what is the acceleration of the crate? a=_________

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Newton’s Third Law of Motion

The horse pulls the cart and the cart pulls the horse in response as per Newton third law. So the big question is, “Don’t the two forces cancel each other? How does the cart accelerate?”