A2.50-cm-diameter parallel-plate capacitor with aspacing of 0.900 mm is charged to 400 VY▼Part AWhat is the total energy stored in the electric field?Express your answer with the appropriate units.Uc=Part BSubmit Request AnswerHAupValueSubmitWhat is the energy density?Express your answer with the appropriate units.HAValue→Request AnswerUnits20BARCE ?BANCUnits?

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A2.50-cm-diameter parallel-plate capacitor with a spacing of 0.900 mm is charged to 400 V Y Y Part A What is the total energy stored in the electric field? Express your answer with the appropriate units. Uc= Value Submit Part B HAS ug = Request Answer What is the energy density? Express your answer with the appropriate units. HA 20 Value Units ? → CE ? Units

A2.50-cm-diameter parallel-plate capacitor with a spacing of 0.900 mm is charged to 400 V Y Y Part A What is the total energy stored in the electric field? Express your answer with the appropriate units. Uc= Value Submit Part B HAS ug = Request Answer What is the energy density? Express your answer with the appropriate units. HA 20 Value Units ? → CE ? Units

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter16: Electrical Energy And Capacitance

Section: Chapter Questions

Problem 35P: a parallel-plate capacitor with area 0.200 m2 and plate separation of 3.00 mm is connected to a...

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(a) A certain parallel-plate capacitor has plates of area 4.00 m2 , separated by 0.0100 mm of nylon, and stores 0.170 C of charge. What is the applied voltage? (b) What is unreasonable about this result? (c) Which assumptions are responsible or inconsistent?
A spherical capacitor is formed from two concentric spherical conducting spheres separated by vacuum. Tire inner sphere has radius 12.5 cm and the outer sphere has radius 14.8 cm. A potential difference of 120 V is applied to the capacitor, (a) What is the capacitance of the capacitor? tb) What is the magnitude of the electrical field at r = 12.6 cm, just outside the inner sphere? (c) What is the magnitude of the electrical field at r = 14.7 cm, just inside the outer sphere? (d) For a parallel-plate capacitor the electrical field is uniform in the region between the plates, except near the edges of the plates. Is this also true for a spherical capacitor?
A 60.0-pF vacuum capacitor has a plate area of 0.010 m2. What is the separation between its plates?
Unreasonable Results (a) An 8.00 F capacitor is connected in parallel to another capacitor, producing a total capacitance of 5.00 F. What is the capacitance of the second capacitor? (b) What is unreasonable about this result? (C) Which assumptions are unreasonable or inconsistent?
a parallel-plate capacitor with area 0.200 m2 and plate separation of 3.00 mm is connected to a 6.00-V battery. (a) What is the capacitance? (b) How much charge is stored on the plates? (c) What is the electric field between the plates? (d) Find the magnitude of the charge density on each plate. (e) Without disconnecting the battery, the plates are moved farther apart. Qualitatively, what happens to each of the previous answers?
A parallel-plate capacitor with plates of area LW and plate separation t has the region between its plates filled with wedges of two dielectric materials as shown in Figure P25.48. Assume t is much less than both L and W. (a) Determine its capacitance. (b) Should the capacitance be the same if the labels 1 and 2 are interchanged? Demonstrate that your expression does or does not have this property. (c) Show that if 1 and 2 approach equality to a common value , your result becomes the same as the capacitance of a capacitor containing a single dielectric: C = 0LW/t. Figure P25.48
Consider the combination of capacitors in Figure P16.42. (a) Find the equivalent single capacitance of the two capacitors in series and redraw the diagram (called diagram 1) with this equivalent capacitance. (b) In diagram 1, find the equivalent capacitance of the three capacitors in parallel and redraw the diagram as a single battery and single capacitor in a loop. (c) Compute the charge on the single equivalent capacitor. (d) Returning to diagram 1, compute the charge on each individual capacitor. Does the sum agree with the value found in part (c)? (e) What is the charge on the 24.0-F capacitor and on the 8.00-F capacitor? Compute the voltage drop across (f) the 24.0-F capacitor and (g) the 8.00-F capacitor. Figure P16.42
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