A 57.5-kg box is pulled by a rope making an angle of θ = 23.5° with the horizontal. The tension in the rope is 33.0 N. (Assume the surface the box slides across is frictionless.)If the box starts from rest, determine the time required to move the box a horizontal distance of 2.53 m

Question
Asked Nov 6, 2019
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A 57.5-kg box is pulled by a rope making an angle of 

θ = 23.5°

 with the horizontal. The tension in the rope is 

33.0 N.

 (Assume the surface the box slides across is frictionless.)

If the box starts from rest, determine the time required to move the box a horizontal distance of 

2.53 m
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Expert Answer

Step 1

The horizontal component of force by rope is

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F F cose =(33.0N) cos 23.5° =30.26N

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Step 2

Then the acceleration of the block i...

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F 3 та, т 30.26 N 57.5kg 0.526m

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