Answered: A 8.00-kg object undergoes an…

Physics for Scientists and Engineers: Foundations and Connections

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ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter5: Newton's Laws Of Motion

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Hi, I have this question answered with the following data:

Question: A 8.00-kg object undergoes an acceleration given by = (4.00 î + 9.00 ĵ) m/s².

Find the resultant force acting on the object.
Find the magnitude of the resultant force.

Given data:

Given data: mass (m) = 8.00 kg, acceleration a = (4.00 î + 9.00 ĵ) m/s²

Required: The resultant force and magnitude of the resultant force

According to newton's second law of motion

F = ma= 8.00 kg(4.00 î + 9.00 ĵ) m/s2= (32.0 î + 72.0 ĵ) N

The resultant force acting on the object is (32.0 î + 72.0 ĵ) N

[can you please explain to me how do you arrived to the 78.8N] - I don't get it! Thanks

The magnitude of the resultant force

F = Fx2 + Fy2= 32.0 N2+72.0 N2= 78.79 N≈ 78.8 N

The magnitude of the resultant force is equals to 78.8 N

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A 8.00-kg object undergoes an acceleration given by = (4.00 î + 9.00 ĵ) m/s2. Find the resultant force acting on the object. Find the magnitude of the resultant force.