A balloon of gas has a  pressure of 1.72 atm, temperature of 35 oC and volume of 2.9 L.  If the temperature decreases to 18 oC and the pressure increase to 3.51 atm, what is the new volume in L?

Chemistry by OpenStax (2015-05-04)
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Chapter9: Gases
Section: Chapter Questions
Problem 53E: What is the molar mass of a gas if 0.281 g of the gas occupies a volume of 125 mL at a temperature...
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A balloon of gas has a  pressure of 1.72 atm, temperature of 35 oC and volume of 2.9 L.  If the temperature decreases to 18 oC and the pressure increase to 3.51 atm, what is the new volume in L?

Expert Solution
Step 1

The combined gas law is a combination of Boyle's law, Charles law, and Gay-Lussac''s law given as:

PVT=k

where k is constant.

Step 2

Given data is:

P1=1.72 atmT1=350C =35+273K=308KV1=2.9LP2=3.51atmT2=180C= 18+273K= 291KV2= to calculate

Putting the given data in combined gas law as:

P1V1T1=P2V2T2V2=P1V1T2T1P2=1.72atm×2.9L×291K308K×3.51atm=1451.5081081.08L=1.342L

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