According to Aristotle’s density equation, if 4.686 grams of the sugar glucose (C6H12O6) occupies a volume of 3.0 cubic centimeters, then glucose must have a density of: 14.058 grams/cm3 7.686 grams/cm3 1.686 grams/cm3 1.562 grams/cm3 0.6402 grams/cm3
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According to Aristotle’s density equation, if 4.686 grams of the sugar glucose (C6H12O6) occupies a volume of 3.0 cubic centimeters, then glucose must have a density of:
- 14.058 grams/cm3
- 7.686 grams/cm3
- 1.686 grams/cm3
- 1.562 grams/cm3
- 0.6402 grams/cm3
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- How many grams of glucose (C6H2O6 molecular mass =180daltons) would be present in one liter of a 1M (molar) solution of glucose?The following equation shows the reaction of baking soda (NaHCO3) and hydrochloric acid (HCl). NaHCO3+HCl → CO2+H2O+NaCl If you have 3.0 grams of NaHCO3, how many moles of HCl are needed for a complete relation?Based on the Henderson-Hasselbalch equation (shown below), calculate the pH when the ratio of acetic acid to acetate is 10 to 1 (the pKa of acetic acid is 4.76). A. 1.00 B. 3.76 C. 4.76 D. 5.76
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