According to Descartes' Rule of Signs, how many negative zeros could the polynomial -3z + 2x® – 2x2 + 3z – 1 have? O negative zeros 1 negative zero O or 2 negative zeros 1 or 3 negative zeros

Algebra and Trigonometry (MindTap Course List)
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Author:James Stewart, Lothar Redlin, Saleem Watson
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Chapter3: Polynomial And Rational Functions
Section3.4: Real Zeros Of Polynomials
Problem 2E
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According to Descartes' Rule of Signs, how many negative zeros
could the polynomial -3x + 2x – 2x2 + 3x – 1 have?
O negative zeros
1 negative zero
O or 2 negative zeros
1 or 3 negative zeros
Transcribed Image Text:1 2 3 4 5 E VIEW LIST According to Descartes' Rule of Signs, how many negative zeros could the polynomial -3x + 2x – 2x2 + 3x – 1 have? O negative zeros 1 negative zero O or 2 negative zeros 1 or 3 negative zeros
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