According to the ideal gas law, a 10.24 mol sample of xenon gas in a 0.8381 L container at 499.4 K should exert a pressure of 500.7 atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Xe gas, a 4.194 L2atm/mol² and b 5.105×102 L/mol. Percent difference = |Pideal - Pvan der Waals x 100 Pideal + Pvan der Waals % 2
According to the ideal gas law, a 10.24 mol sample of xenon gas in a 0.8381 L container at 499.4 K should exert a pressure of 500.7 atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For Xe gas, a 4.194 L2atm/mol² and b 5.105×102 L/mol. Percent difference = |Pideal - Pvan der Waals x 100 Pideal + Pvan der Waals % 2
Chemistry & Chemical Reactivity
10th Edition
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter10: Gases And Their Properties
Section: Chapter Questions
Problem 53PS: In the text, it is stated that the pressure of 4.00 mol of Cl2 in a 4.00-L tank at 100.0 C should be...
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![According to the ideal gas law, a 10.24 mol sample of xenon gas in a 0.8381 L container at 499.4 K should exert a pressure of 500.7
atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For
Xe gas, a 4.194 L2atm/mol² and b 5.105×102 L/mol.
Percent difference =
|Pideal - Pvan der Waals
x 100
Pideal + Pvan
der Waals
%
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F70d8024b-c278-4bff-bf91-da5bc323109a%2Ffd71ffb3-05a9-482d-b92f-c13f0b3feb11%2Fvokmmll_processed.jpeg&w=3840&q=75)
Transcribed Image Text:According to the ideal gas law, a 10.24 mol sample of xenon gas in a 0.8381 L container at 499.4 K should exert a pressure of 500.7
atm. What is the percent difference between the pressure calculated using the van der Waals' equation and the ideal pressure? For
Xe gas, a 4.194 L2atm/mol² and b 5.105×102 L/mol.
Percent difference =
|Pideal - Pvan der Waals
x 100
Pideal + Pvan
der Waals
%
2
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