Ackermann's Function is a recursive mathematical algorithm that can be used to test how well a computer performs recursion. Write a function A(m, n) that solves Ackermann's Function. Use the following logic in your function: If m = 0 then return n + 1 If n = 0 then return A(m-1, 1) Otherwise, return A(m-1, A(m, n-1)) Test your function in a driver program that displays the following values: A(0, 0) A(0, 1) A(1, 1) A(1, 2) A(1, 3) A(2, 2) A(3, 2)

C++ Programming: From Problem Analysis to Program Design
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ISBN:9781337102087
Author:D. S. Malik
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Chapter15: Recursion
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19-12) Ackermann's Function
Ackermann's Function is a recursive mathematical algorithm that can be used to test how well a computer performs recursion. Write a function
A(m, n) that solves Ackermann's Function. Use the following logic in your function:
If m = 0 then return n + 1
If n = 0 then return A(m-1, 1) Otherwise, return A(m-1, A(m, n-1))
Test your function in a driver program that displays the following values:
A(0, 0) A(0, 1) A(1, 1) A(1, 2) A(1, 3) A(2, 2) A(3, 2)
SAMPLE RUN #0: ./AckermannRF
Interactive Session
Hide Invisibles
Highlight: None
Show Highlighted Only
The value of A(0, -0) =-14
The value of .A(0, ·1) =- 24
The value of A(1, .1)=.34
The value of A(1, 2)=.44
The value of .A(1, .3) =- 54
The value of ·A(2, 2) =.7
The value of A(3, -2)=- 294
Transcribed Image Text:19-12) Ackermann's Function Ackermann's Function is a recursive mathematical algorithm that can be used to test how well a computer performs recursion. Write a function A(m, n) that solves Ackermann's Function. Use the following logic in your function: If m = 0 then return n + 1 If n = 0 then return A(m-1, 1) Otherwise, return A(m-1, A(m, n-1)) Test your function in a driver program that displays the following values: A(0, 0) A(0, 1) A(1, 1) A(1, 2) A(1, 3) A(2, 2) A(3, 2) SAMPLE RUN #0: ./AckermannRF Interactive Session Hide Invisibles Highlight: None Show Highlighted Only The value of A(0, -0) =-14 The value of .A(0, ·1) =- 24 The value of A(1, .1)=.34 The value of A(1, 2)=.44 The value of .A(1, .3) =- 54 The value of ·A(2, 2) =.7 The value of A(3, -2)=- 294
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