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Activity 4A: I conduct performance ratings for two employees of the same nature of work using the Westinghouse Rating System.     The observed time for an operator to finish a task which is tightening of screws for 2 minutes. His ratings were noted, as follows: Good skill,                      C1 + 0.06 Excellent Efforts,           B1 + 0.08 Average condition,         C  + 0.02 Good consistency,         C  + 0.01 Total Westinghouse Rating + 0.17 The normal time for that operation would be = 2.0 x 1.17 = 2.34 min. To find the standard time at 20% allowance,                                       = 2.34  x           100         = 2.92 min.                                                            (100 – 20)      Explain. Be able to describe your basis, or give comments, on how you came up with their total rating. Set the standard time at 20% allowance.

Activity 4A: I conduct performance ratings for two employees of the same nature of work using the Westinghouse Rating System.     The observed time for an operator to finish a task which is tightening of screws for 2 minutes. His ratings were noted, as follows: Good skill,                      C1 + 0.06 Excellent Efforts,           B1 + 0.08 Average condition,         C  + 0.02 Good consistency,         C  + 0.01 Total Westinghouse Rating + 0.17 The normal time for that operation would be = 2.0 x 1.17 = 2.34 min. To find the standard time at 20% allowance,                                       = 2.34  x           100         = 2.92 min.                                                            (100 – 20)      Explain. Be able to describe your basis, or give comments, on how you came up with their total rating. Set the standard time at 20% allowance.

Practical Management Science
Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter2: Introduction To Spreadsheet Modeling
Section: Chapter Questions
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Activity 4A:

I conduct performance ratings for two employees of the same nature of work using the Westinghouse Rating System.  

 

The observed time for an operator to finish a task which is tightening of screws for 2 minutes. His ratings were noted, as follows:

Good skill,                      C1 + 0.06

Excellent Efforts,           B1 + 0.08

Average condition,         C  + 0.02

Good consistency,         C  + 0.01

Total Westinghouse Rating + 0.17

The normal time for that operation would be = 2.0 x 1.17 = 2.34 min.

To find the standard time at 20% allowance,

                                      = 2.34  x           100         = 2.92 min.

                                                           (100 – 20)   

 

Explain.

Be able to describe your basis, or give comments, on how you came up with their total rating. Set the standard time at 20% allowance.

Conditions Ideal A-+ 0.06 Skill Effort Consistency Perfect Super AI -+ 0.15 A2 - + 0.13 Excellent Excessive Al-+ 0.13 A2-+ 0.12 Excellent A -+ 0.04 Excellent B-+ 0.03 Excellent B1 -+ 0.10 B2 -+0.08 B-+ 0.04 B1 -+ 0.11 B2 -+ 0.08 Good Good C-+ 0.0O Good Good CI - + 0.06 C2 - + 0.03 C=+ 0.00 CI - + 0.OS C2 - + 0.02 Average Average D- 0.00 D- 0.00 Fair El -- 0.04 Average D- 0.00 Fair Average D- 0.00 Fair Fair E--0.03 E-- 0.02 El -- 0.0s E2 -- 0.1o E2 - 0.08 Poor Poor Poor Poor F -- 0.07 F-- 0.04 F1 -- 0.16 F2 -- 0.22 FI -- 0.12 F2 -- 0.17 Note: Correction on Conditions, C = 0.02; Consistency, C = 0.01 Summarized formula for calculation: Westinghouse rating = Sum of ratings, i.e. rating of (Skill + Effort + Conditions + Consistency) as given in Westinghouse tables. Rating Factor = 1 ± Westinghouse Rating Normal Time = Observed time x Rating factor 100 Standard Time = Normal Time x (100 – Total allowances in percentage) -
Transcribed Image Text:Conditions Ideal A-+ 0.06 Skill Effort Consistency Perfect Super AI -+ 0.15 A2 - + 0.13 Excellent Excessive Al-+ 0.13 A2-+ 0.12 Excellent A -+ 0.04 Excellent B-+ 0.03 Excellent B1 -+ 0.10 B2 -+0.08 B-+ 0.04 B1 -+ 0.11 B2 -+ 0.08 Good Good C-+ 0.0O Good Good CI - + 0.06 C2 - + 0.03 C=+ 0.00 CI - + 0.OS C2 - + 0.02 Average Average D- 0.00 D- 0.00 Fair El -- 0.04 Average D- 0.00 Fair Average D- 0.00 Fair Fair E--0.03 E-- 0.02 El -- 0.0s E2 -- 0.1o E2 - 0.08 Poor Poor Poor Poor F -- 0.07 F-- 0.04 F1 -- 0.16 F2 -- 0.22 FI -- 0.12 F2 -- 0.17 Note: Correction on Conditions, C = 0.02; Consistency, C = 0.01 Summarized formula for calculation: Westinghouse rating = Sum of ratings, i.e. rating of (Skill + Effort + Conditions + Consistency) as given in Westinghouse tables. Rating Factor = 1 ± Westinghouse Rating Normal Time = Observed time x Rating factor 100 Standard Time = Normal Time x (100 – Total allowances in percentage) -
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