(1) A course repeater claims that his brother who did some Calculus at college years ago, but currently on some cough medication, believes that the first derivative of 4x (2x2 — 1)(х2 + 3) 2х 2х (2x2 —1)(х2 + 3) f(x) = -is f'(x) = x2 + 1 [2x² – 1 ' x² +3 x2 + 11 x2 +1 and (x² + 8)7 (2 – 3x2)5 Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you (x² + 8)7 Lx2 + 8 2-Зх2] |(2— Зx?)5| 14x is g'(x) = 30x + that the first derivative of g(x) = confirm whether his brother is right, wrong or a little tipsy.
(1) A course repeater claims that his brother who did some Calculus at college years ago, but currently on some cough medication, believes that the first derivative of 4x (2x2 — 1)(х2 + 3) 2х 2х (2x2 —1)(х2 + 3) f(x) = -is f'(x) = x2 + 1 [2x² – 1 ' x² +3 x2 + 11 x2 +1 and (x² + 8)7 (2 – 3x2)5 Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you (x² + 8)7 Lx2 + 8 2-Зх2] |(2— Зx?)5| 14x is g'(x) = 30x + that the first derivative of g(x) = confirm whether his brother is right, wrong or a little tipsy.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![(1) A course repeater claims that his brother who did some Calculus at college years ago, but
currently on some cough medication, believes that the first derivative of
4x
(2x2 — 1)(х2 + 3)
2х
2х
(2x2 —1)(х2 + 3)
f(x) =
-is f'(x) =
x2 + 1
[2x² – 1 ' x² +3
x2 + 11
x2 +1
and
(x² + 8)7
(2 – 3x2)5
Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you
(x² + 8)7
Lx2 + 8 2-Зх2] |(2— Зx?)5|
14x
is g'(x) =
30x
+
that the first derivative of g(x) =
confirm whether his brother is right, wrong or a little tipsy.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fad0ebfe9-34e5-496e-87e2-1620f8a73549%2F6b4f2821-11a4-42d1-ac67-30dc5bdf23a1%2F0gkk5l_processed.png&w=3840&q=75)
Transcribed Image Text:(1) A course repeater claims that his brother who did some Calculus at college years ago, but
currently on some cough medication, believes that the first derivative of
4x
(2x2 — 1)(х2 + 3)
2х
2х
(2x2 —1)(х2 + 3)
f(x) =
-is f'(x) =
x2 + 1
[2x² – 1 ' x² +3
x2 + 11
x2 +1
and
(x² + 8)7
(2 – 3x2)5
Using the product, qoutient and chain rules you learnt in Unit 7 of this Course, could you
(x² + 8)7
Lx2 + 8 2-Зх2] |(2— Зx?)5|
14x
is g'(x) =
30x
+
that the first derivative of g(x) =
confirm whether his brother is right, wrong or a little tipsy.
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