Question 2 Determine the forces in members BC and FG of the loaded symmetrical truss. D 12 300 lb 6 200 lb OF 6 100 lb B G 6 O O BC -- 300 lb T. FG - 15o lb C O O BC = 300 lb C. FG = - 150 Ib T O O BC - 300 Ib C. FG - 150 lb C O O BC -- 300 Ib C. FG - 150 lb T O O BC = 300 Ib T, FG = 150 lb C O O BC = - 300 Ib T. FG = - 150 lb c O O BC -- 150 Ib T, FG - 150 lb C O O BC -- 150 Ib C. FG = 150 lb T O O BC = - 150 Ib T, FG -- 150 Ib T O O BC -- 150 Ib C. FG - 150 Ib C O O BC - 150 Ib C, FG -- 150 Ib T O O BC = 150 lb C, FG = - 150 Ib C O O BC -- 300 Ib C. FG - 150 Ib C O O BC = - 300 Ib C. FG = 150 lb c O O BC -- 150 lb C, FG = - 150 lb C Dо вс- з00 b с, FG - 150 lb T O O BC - 150 Ib C. FG - 150 Ibc O O BC - 150 Ilb T, FG = 150 lb T O O BC = - 300o Ib T, FG = - 150 Ib T O O BC = 300 lb T, FG = - 150 lb C O O BC = 300 Ib T, FG = 150 lb T O O BC = 150 lb T, FG = - 150 lb T O O BC = 300 Ib T, FG = - 150 lb T O O BC = - 300 lb T, FG = 150 lb T O O BC = - 300 Ib C. FG = - 150 Ib C O O BC - 150 lb C, FG - 150 Ib T O O BC -- 150 Ib T, FG -- 150 Ibc O O BC - 150 lb T, FG -- 150 Ib C O O BC = - 150 lb T, FG = 150 Ilb T O O BC = 150 Ib T, FG = 150 lb C O O BC = 300 Ib C, FG = - 150 lb C

Question 2 Determine the forces in members BC and FG of the loaded symmetrical truss. D 12 300 lb 6 200 lb OF 6 100 lb B G 6 O O BC -- 300 lb T. FG - 15o lb C O O BC = 300 lb C. FG = - 150 Ib T O O BC - 300 Ib C. FG - 150 lb C O O BC -- 300 Ib C. FG - 150 lb T O O BC = 300 Ib T, FG = 150 lb C O O BC = - 300 Ib T. FG = - 150 lb c O O BC -- 150 Ib T, FG - 150 lb C O O BC -- 150 Ib C. FG = 150 lb T O O BC = - 150 Ib T, FG -- 150 Ib T O O BC -- 150 Ib C. FG - 150 Ib C O O BC - 150 Ib C, FG -- 150 Ib T O O BC = 150 lb C, FG = - 150 Ib C O O BC -- 300 Ib C. FG - 150 Ib C O O BC = - 300 Ib C. FG = 150 lb c O O BC -- 150 lb C, FG = - 150 lb C Dо вс- з00 b с, FG - 150 lb T O O BC - 150 Ib C. FG - 150 Ibc O O BC - 150 Ilb T, FG = 150 lb T O O BC = - 300o Ib T, FG = - 150 Ib T O O BC = 300 lb T, FG = - 150 lb C O O BC = 300 Ib T, FG = 150 lb T O O BC = 150 lb T, FG = - 150 lb T O O BC = 300 Ib T, FG = - 150 lb T O O BC = - 300 lb T, FG = 150 lb T O O BC = - 300 Ib C. FG = - 150 Ib C O O BC - 150 lb C, FG - 150 Ib T O O BC -- 150 Ib T, FG -- 150 Ibc O O BC - 150 lb T, FG -- 150 Ib C O O BC = - 150 lb T, FG = 150 Ilb T O O BC = 150 Ib T, FG = 150 lb C O O BC = 300 Ib C, FG = - 150 lb C

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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