Jastruction:• Can you tell whether the net flux through the Gaussian surface is positive, negalive.A The Caussian cylinder is in a uniform electric field of magnitude E, alignod wich thear anwer abaut the net flux only on a qualitative arguments about the mognitude of the flux throughavtric fields. The end caps are labeled A and C and the side surface is labeled B. In each case, baseIn the following questions, a Gaussian cylinder with radius a and length lis placed in variousend cups and side of the surfaceglinder axis,• Find the sign and magnitude of the flux through:Surface A:Surface B:Surface C:akthe net fux through the Gaussian surface positive, negative, or zero?| The Gaussian cylinder enckoses a negative charge. (The field from part A is removod)• Find the sign of the flux through:Surface A:Surface B:Surface C:• Is the net flux through the Gaussian surface positive, negative, or zero?C. The Gaussian cylinder encloses opposite charges of equal magnitude. (The chargesure on the axis of the cylinder and cquidistant from the center.)• Find the sign of the flux through:Surface A:Surface B:Surface C:* Is the net flux through the Gaussian surface positive, negative, or zero?D. A posicive charge is located above the Gaussian cylinder.• Find the sign of the flux through:Surface A:Surface B:Surface C:or zero? Explain.

We know that the formula of the electric field is given as ϕ= ∫E.dAϕ= qinε0 where the E is the…

aer about the net fluex only on a qualitative arguments about the magnitade of the fha throw In the The Gaussian cylinder is in a uniform clectric field of magniude E, aligned with the • Find the sign and magnitode of the flux through: rie fields. The end caps are labeled A and C and the sidc surface is labeled B. In each case, base dius a and length 1l is placed in various glinder axis. Suface R.

aer about the net fluex only on a qualitative arguments about the magnitade of the fha throw In the The Gaussian cylinder is in a uniform clectric field of magniude E, aligned with the • Find the sign and magnitode of the flux through: rie fields. The end caps are labeled A and C and the sidc surface is labeled B. In each case, base dius a and length 1l is placed in various glinder axis. Suface R.

University Physics Volume 2

18th Edition

ISBN:9781938168161

Author:OpenStax

Publisher:OpenStax

Chapter6: Gauss's Law

Section: Chapter Questions

Problem 61P: An uncharged spherical conductor S of radius R has two spherical cavities A and B of radii a and b,...

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Similar questions

Reformulate Gauss's law by choosing the unit normal of the Gaussian surface to be the one directed inward.
A total charge Q is distributed uniformly throughout a spherical volume that is centered at o1 and has a radius R. Without disturbing the charge remaining charge is removed from the spherical volume that is centered at o2 (see below). Show that the electric field everywhere in the empty region is given by E=Qr40R3 where r is the displacement vector directed from o1 to o2 .
The infinite slab between the planes defined by z=a/2 and z=a/2 contains a uniform volume charge density p (see below). What is the electric field produced by this charge distribution, both inside and outside the distribution?
Shown below ale two concentric conducting spherical shells of radii R1 and R2 , each of finite thickness much less than either radius. The inner and outer shell carry net charges q1 and q2 , respectively, where both q1 and q2 are positive. What is the electric field for (a) rR1 ; (b) R1rR2 , and (c) rR2 ? (d) What is the net charge on the inner surface of the inner shell, the outer surface of the inner shell, the inner surface of the outer shell, and the outer surface of the outer shell?
A square surface of area 2 cm2 is in a space of uniform electric field of magnitude 103 N/C . The amount of flux through it depends on how the square is oriented relative to the direction of the electric field. Find the electric flux through the square, when the normal to it makes the following angles with electric field: (a) 30(, (b) 90(, and (c) 0(. Note that these angles can also be given as 1800 + .
A circular area S is concentric with the origin, has radius a, and lies in the yz-plane. Calculate s E ndA for E=2z2i.
A fellow student calculated the flux through the square for the system in the preceding problem and got 0. What went wrong?
A solid cylindrical conductor of radius a is surrounded by a concentric cylindrical shell of inner radius b. The solid cylinder and the shell carry charges +Q and Q , respectively. Assuming that the length L of both conductors is much greater than a or b, determine the electric field as a function of r, the distance from the common central axis of the cylinders, for (a) ra; (b) arb; and (c) rb.
Suppose that the electric field of an isolated point charge were proportional to 1/r2+ rather than 1/r2 . Determine the flux that passes through the surface of a sphere of radius R centered at the charge. Would Gauss's law remain valid?
A non-uniform thin rod is bent into an arc of radius R. The linear charge density λ of the roddepends on θ and is given byλ =λ0/cos θwhere λ0 is a positive constant. The arc extends from θ =π/4 to θ =3π/4as shown a)Sketch the direction of the resultant electric field at the origin.b) Calculate the magnitude of the electric field E->.
Discuss the possibility of choosing Gaussian surface other than the sphere.For instance what if you choose the cylindrical surface as a Gaussian surface, is it possible to use Gauss’s law in order to calculate the electric fieldof a charged sphere? Explain your answer in detail.
A large non-conducting slab of area A and thickness d has a charge density rho=Cx^4. The origin is through the center of the slab. That is to say, it bisects the slab into two equal volumes of d/2 thickness and with an area of A, with -d/2 to the left of x=0, and d/2 to the right of x=0. Express all answers in terms of C, x, and any known constants. Gaussian surface 1 (cylinder) is located such that its volume encompasses the charge contained within the slab. Apply Gauss's Law to cylinder 1 to determine the electric field to the left and to the right of the slab. Make sure you incude the domains over which the field is valid.