After enjoying a big sandwich at Katz's Delicatessen, you decide to walk back to your luxury suite at the Waldorf-Astoria Hotel. First, you perambulate 0.15 mi at a polar angle of 160 degrees 0.15 mi angle 160^ ) . Next, you skedaddle 1.60 mi at a polar angle of 55 degrees (1.60 mi angle55^ ) . You follow this with a 0.55 mi jaunt at a polar angle of 150 degrees (0.55 mi angle150^ ) Finally, you be-bop 0.82 mi at a polar angle of 60 degrees (0.82 mi angle 60^ ) . What is the overall displacement from your starting point at Katz's Delicatessen? Express your answer in polar notation.
After enjoying a big sandwich at Katz's Delicatessen, you decide to walk back to your luxury suite at the Waldorf-Astoria Hotel. First, you perambulate 0.15 mi at a polar angle of 160 degrees 0.15 mi angle 160^ ) . Next, you skedaddle 1.60 mi at a polar angle of 55 degrees (1.60 mi angle55^ ) . You follow this with a 0.55 mi jaunt at a polar angle of 150 degrees (0.55 mi angle150^ ) Finally, you be-bop 0.82 mi at a polar angle of 60 degrees (0.82 mi angle 60^ ) . What is the overall displacement from your starting point at Katz's Delicatessen? Express your answer in polar notation.
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter2: Vectors
Section: Chapter Questions
Problem 59P: At one point in space, the direction of the electric field vector Is given In the Cartesian system...
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After enjoying a big sandwich at Katz's Delicatessen, you decide to walk back to your luxury suite at the Waldorf-Astoria Hotel. First, you perambulate 0.15 mi at a polar angle of 160 degrees 0.15 mi angle 160^ ) . Next, you skedaddle 1.60 mi at a polar angle of 55 degrees (1.60 mi angle55^ ) . You follow this with a 0.55 mi jaunt at a polar angle of 150 degrees (0.55 mi angle150^ ) Finally, you be-bop 0.82 mi at a polar angle of 60 degrees (0.82 mi angle 60^ ) . What is the overall displacement from your starting point at Katz's Delicatessen? Express your answer in polar notation.
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Net displacement in x direction
Net displacement in y direction
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