After how many time ticks, will L's distance vector (i.e., its DV that it exchanges with its neighbor) reflect this change in topology?
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- 5.03-3. Dijkstra's Algorithm (3, part 3). Consider the network shown below, and Dijkstra’s link-state algorithm. Here, we are interested in computing the least cost path from node E to all other nodes using Dijkstra's algorithm. Using the algorithm statement used in the textbook and its visual representation, complete the "Step 2" row in the table below showing the link state algorithm’s execution by matching the table entries (i), (ii), (iii), (iv) and (v) with their values.Consider a system with four page frames and a program that uses eight pages. Consider the reference string 0 1 7 2 0 3 1 7 0 1 7 and assume that all four page frames are initially empty. Consider the three following algorithms: a. Optimal page replacement In each cases show a diagram (ASCII art recommended) that shows which pages are in which frames throughout time, and page faults at the bottom. For instance: The first 4 steps is ALWAYS the same (i.e., just fill the four frames, with one page fault each time)link(a,b). link(a,c). link(b,c). link(b,d). link(c,d). link(d,e). link(d,f). link(e,f). link(f,g). Using The above Formulate the appropriate Prolog predicate "path(X,Y,N)" which is true if (and only if) there is a path of length "N" from node "X" to node "Y". For example, there is a path of length 2 from "a" to "d": "a->b->d", but also "a->c->d", and so "path(a,d,2)" gives "true" (two times). There is also a path of length 3 from "a" to "d": "a->b->c->d". Test this predicate out on the above network to verify whether or not it is working correctly. Once this is working correctly, note now, that e.g., "path(a,e,N)." will give multiple answers:
- Suppose the economies of the world use a set of currencies C1, . . . , Cn; think of these as dollars, pounds, Bitcoin, etc. Your bank allows you to trade each currency Ci for any other currency Cj, and finds some way to charge you for this service. Suppose that for each ordered pair of currencies (Ci, Cj ), the bank charges a flat fee of fij > 0 dollars to exchange Ci for Cj (regardless of the quantity of currency being exchanged). Describe an algorithm which, given a starting currency Cs, a target currency Ct, and a list of fees fij for all i, j ∈ {1, . . . , n}, computes the cheapest way (that is, incurring the least in fees) to exchange all of our currency in Cs into currency Ct. Also, justify the its runtime. [A description or pseudocode (either is OK) of the algorithm, as well as a brief justification of its runtime.]Consider the (directed) network in the attached document We could represent this network with the following Prolog statements: link(a,b). link(a,c). link(b,c). link(b,d). link(c,d). link(d,e). link(d,f). link(e,f). link(f,g). Now, given this network, we say that there is a "connection" from a node "X" to a node "y" if we can get from "X" to "Y" via a series of links, for example, in this network, there is a connection from "a" to "d", and a connection from "c" to "f", etc.Recall that histograms are used for constructing load-balanced range partitions. Suppose you have a histogram where values are between 1 and 100, and are partitioned into 10 ranges, 1–10, 11–20,...,91–100, with frequencies 15, 5, 20, 10, 10, 5, 5, 20, 5, and 5, respectively. Give a load-balanced range partitioning function to divide the values into 5 partitions. Write an algorithm for computing a balanced range partition with p partitions, given a histogram of frequency distributions containing n ranges.
- give an example of a network with no more than 6 nodes and define all the data structure used by a distence vector and a link state algorithm. perform one iteration for both the algorithm families and show the aforementioned structires are uptadedPLEASE USE PYTHONGiven a jungle matrix NxM:jungle = [ [1, 0, 0, 0], [1, 1, 0, 1], [0, 1, 0, 0], [1, 1, 1, 1,]]Where 0 means the block is dead end and 1 means the block can be used in the path fromsource to destination.Task:Starting at position (0, 0), the goal is to reach position (N-1, M-1).Your program needs to build and output the solution matrix – a 4x4 matrix with 1’s inpositions used to get from the starting position (0,0) to the ending position (N-1,M-1)with the following constraints:You can only move one space at a timeYou can only in two directions: forward and down.You can only pass thru spaces on the jungle matrix marked ‘1’If you cannot reach the ending position – print a message that you’re trapped in thejungleAlgorithm:If destination is reachedprint the solution matrixElseMark current cell in the solution matrixMove forward horizontally and recursively check if this leads to a solution If there is no solution, move down and recursively check if this leads to a solution If…link(a,b). link(a,c). link(b,c). link(b,d). link(c,d). link(d,e). link(d,f). link(e,f). link(f,g). Using the above Formulate the appropriate Prolog predicate "path(X,Y,N)" which is true if (and only if) there is a path of length "N" from node "X" to node "Y". For example, there is a path of length
- Correct answer will be upvoted else downvoted. Computer science. You are approached to pick some integer k (k>0) and find a succession an of length k with the end goal that: 1≤a1<a2<⋯<ak≤|s|; ai−1+1<ai for all I from 2 to k. The characters at positions a1,a2,… ,ak are taken out, the excess characters are linked without changing the request. Thus, at the end of the day, the situations in the arrangement an ought not be contiguous. Allow the subsequent to string be s′. s′ is called arranged if for all I from 2 to |s′| s′i−1≤s′i. Does there exist such a grouping a that the subsequent string s′ is arranged? Input The main line contains a solitary integer t (1≤t≤1000) — the number of testcases. Then, at that point, the portrayals of t testcases follow. The main line of each testcase contains a string s (2≤|s|≤100). Each character is either '0' or '1'. Output For each testcase print "YES" if there exists a grouping a to such an extent that…A = [15, 12, 13, 19, 14, 10, 16, 20, 9, 18, 8, 7]B = [19, 14, 8, 16, 20, 9, 18, 15, 12, 13, 7, 10]vN = 0for i in range(len (A)):vN = A[i]for j in range(len (B)):if B[j] ==vN:print ('A[',i,'] with B[',j,']') implementation this code with JUST one for loopHippity hoppity, abolish loopity def frog_collision_time(frog1, frog2): A frog hopping along on the infinite two-dimensional lattice grid of integers is represented as a 4- tuple of the form (sx, sy, dx, dy) where (sx, sy) is its starting position at time zero, and (dx, dy) is its constant direction vector for each hop. Time advances in discrete integer steps 0, 1, 2, 3, ... so that each frog makes one hop at every tick of the clock. At time t, the position of that frog is given by the formula (sx+t*dx, sy+t*dy) that can be nimbly evaluated for any t. Given two frogs frog1 and frog2 that are guaranteed to initially stand on different squares, return the time when both frogs hop into the same square. If these two frogs never simultaneously arrive at the same square, return None. This function should not contain any loops whatsoever. The result should be calculated using conditional statements and integer arithmetic. Perhaps the best way to get cracking is to first solve a simpler…