Amy and Richard each solved an equation using the quadratic formula. Amy's Equation and Method 4x² + 7x-20 = 0 Step 1: x = Step 2: x = Step 3: x = Step 4: x = Step 1: x = Step 2: x = Step 3: x = Step 4: x = -7± 72 Richard's Equation and Method x² - 6x +8=0 Step 5: x = 2(4) -7+√49-80 8 -7± √-31 8 -7±i√31 8 4(1)(20) 6± √(-6)² − 4(1)(8) 2(1) 6± √4 2 6± √36-32 2 6+√4 2 and x = 6-√4 2 6+2 and z = 6 - 2i 2 2 Step 6:4 and x = 3 - i

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.3: Quadratic Equations
Problem 82E
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Amy and Richard each solved an equation using the quadratic formula.
Amy's Equation and Method
4x² + 7x-20 = 0
Step 1: x =
Step 2: x =
Step 3: x =
Step 4: x =
Step 1: x =
Step 2: x =
Step 3: x =
Richard's Equation and Method
x² - 6x +8=0
Step 4: x =
-7± 72 4(1)(20)
2(4)
Step 5: x =
-7√49-80
8
-7± √-31
8
-7±i√31
8
6± √(-6)²4(1)(8)
2(1)
6± √36-32
2
6± √4
2
6+√4
2
6+2
2
and x =
and x =
6-√4
2
6-2i
2
Step 6: x4 and x = 3 - i
Both students made a mistake.
1. Describe the mistake each student made.
2. Explain what each student needs to do to fix their mistake.
Transcribed Image Text:Amy and Richard each solved an equation using the quadratic formula. Amy's Equation and Method 4x² + 7x-20 = 0 Step 1: x = Step 2: x = Step 3: x = Step 4: x = Step 1: x = Step 2: x = Step 3: x = Richard's Equation and Method x² - 6x +8=0 Step 4: x = -7± 72 4(1)(20) 2(4) Step 5: x = -7√49-80 8 -7± √-31 8 -7±i√31 8 6± √(-6)²4(1)(8) 2(1) 6± √36-32 2 6± √4 2 6+√4 2 6+2 2 and x = and x = 6-√4 2 6-2i 2 Step 6: x4 and x = 3 - i Both students made a mistake. 1. Describe the mistake each student made. 2. Explain what each student needs to do to fix their mistake.
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