Upload your handwritten solution in the box below the question along withthe integrity statement, your ID, your name and your signature.An 8-turn circular coil of radius r 13 (cm] is sitting in a uniform magnetic field that isperpendicular to the plane of the coil. The magnitude of the magnetic field changes toproduce an EMF = 6 [V].%3!The magnitude of the rate of change of the magnetic field, ldB/dt|, is givena.by:6.6.O 8xT+0.13 xcos908xT*132 xcos90°8хт*0.13?b.Calculate IdB/dtj.IdB/dt| =(T/s]

GivenN=8 turns r=13 cm=0.13 mε=6 V

Answered: An 8-turn circular coil of radius r =…

An 8-turn circular coil of radius r = 13 [cm] is sitting in a uniform mag perpendicular to the plane of the coil. The magnitude of the magnetic produce an EMF = 6 [V]. %3D %3D

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Hi, and thank you for your explanation BUT I still a little lost with your details since what I learned in class was with a formula F=ILBsinθ where θ is the angle between the wire and the magnetic field. The force is perpendicular to the field and the current. The equivalent formula for the force on a moving charged particle of charge q and velocity v is F, equals, q, v, B, sine, theta,F=qvBsinθ, with the force perpendicular to field and velocity. Can you please go in more detail description of your results - thanks!!
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