An 8V battery is connected in series in order to power light bulbs A and B as seen in the image below. The resistance of light bulb A is 30 ohms, and the resistance of light bulb B is 15 ohms. How does the current through light bulb A compare with the current of light bulb B? • A. The current through light bulb A is exactly double that through light bulb B. OB. The current through both light bulbs are the same OC. The current through light bulb A is less than light bulb B

An 8V battery is connected in series in order to power light bulbs A and B as seen in the image below. The resistance of light bulb A is 30 ohms, and the resistance of light bulb B is 15 ohms. How does the current through light bulb A compare with the current of light bulb B? • A. The current through light bulb A is exactly double that through light bulb B. OB. The current through both light bulbs are the same OC. The current through light bulb A is less than light bulb B

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter21: Circuits And Dc Instruments

Section: Chapter Questions

Problem 26PE: A person with body resistance between his hands of 1.00 k accidentally grasps the terminals of a...

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A person with body resistance between his hands of 10.0k accidentally grasps the terminals of a20.0-kV power supply. (Do NOT do this!) (a) Draw a circuit diagram to represent the situation, (b) If the internal resistance of the power supply is 2000 , what is thecurrent through his body? (c) What is the power dissipated in his body? (d) If the power supply is to be made safe by increasing its internal resistance, what should the internal resistance be for the maximum current in this situation to be 1.00 mA or less? (e) Will this modification compromise the effectiveness of the power supply for driving low- resistance devices? Explain your reasoning.
Consider the circuit shown in Figure P18.10. (a) Calculate the equivalent resistance of the 10.0- and 5.00- resistors connected in parallel. (b) Using the result of part (a), calculate the combined resistance of the 10.0-, 5.00-, and 4.00- resistors. (c) Calculate the equivalent resistance of the combined resistance found in part (b) and the parallel 3.00- resistor. (d) Combine the equivalent resistance found in part (c) with the 2.00- resistor. (e) Calculate the total current in the circuit. (f) What is the voltage drop across the 2.00- resistor? (g) Subtracting the result of part (f) from the battery voltage, find the voltage across the 3.00- resistor. (h) Calculate the current in the 3.00- resistor. Figure P18.10
A person with body resistance between his hands of 1.00 k accidentally grasps the terminals of a 20.0-kV power supply. (Do NOT do this!) (a) Draw a circuit diagram to represent the situation. (b) If the internal resistance of the power supply is 2000 , what is the current through his body? (c) What is the power dissipated in his body? (d) If the power supply is to be made safe by increasing its internal resistance, what should the internal resistance be for the maximum current in this situation to be 1.00 mA or less? (e) Will this modification compromise the effectiveness of the power supply for driving low-re si stance devices? Explain your reasoning,
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