An AC voltage source and a resistor are connected in series to make up a simple AC circuit. If the source voltage is given by v = Vo sin(2aft) and the source frequency is 14.5 Hz, at what time t will the current flowing in this circuit be 52.0% of the peak current? ms

An AC voltage source and a resistor are connected in series to make up a simple AC circuit. If the source voltage is given by v = Vo sin(2aft) and the source frequency is 14.5 Hz, at what time t will the current flowing in this circuit be 52.0% of the peak current? ms

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter33: Inductors And Ac Circuits

Section: Chapter Questions

Problem 80PQ

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Question

An AC voltage source and a resistor are connected in series to make up a
simple AC circuit. If the source voltage is given by v= Vo sin(2aft) and the source
frequency is 14.5 Hz, at what time t will the current flowing in this circuit be
52.0% of the peak current?
ms

Expert Solution

Step 1

Given,

$V = V_{0} \sin (2 πft)$

Frequency f = 14.5 Hz

We know the expression for voltage is

$V = IR$

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