An air-filled capacitor consists of two parallel plates, each with an area of 9.20 cm2 separated by a distance of 1.80 mm. A 16.0-V potential difference is applied to these plates. Calculate the charge on each plate. Calculate your result in the form of X × 10-12 C, round the value of X to the nearest 0.01and enter it as your answer. For example, if you get 1.234 x 10-12, you type in 1.23. Take vacuum permittivity to be 8.85 x10-12

Principles of Physics: A Calculus-Based Text
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ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter20: Electric Potential And Capacitance
Section: Chapter Questions
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An air-filled capacitor consists of two parallel plates, each with an area of 9.20 cm2
separated by a distance of 1.80 mm. A 16.0-V potential difference is applied to these
plates. Calculate the charge on each plate. Calculate your result in the form of X ×
10-12
C, round the value of X to the nearest 0.01and enter it as your answer.
For example, if you get 1.234 x 10-12, you type in 1.23.
Take vacuum permittivity to be 8.85 x10-12
Transcribed Image Text:An air-filled capacitor consists of two parallel plates, each with an area of 9.20 cm2 separated by a distance of 1.80 mm. A 16.0-V potential difference is applied to these plates. Calculate the charge on each plate. Calculate your result in the form of X × 10-12 C, round the value of X to the nearest 0.01and enter it as your answer. For example, if you get 1.234 x 10-12, you type in 1.23. Take vacuum permittivity to be 8.85 x10-12
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