2.4 An analytical chemist weighs out 0.074 g of an unknown monoprotic acid into a 250 mL volumetric flask and dilutes to the mark with distilled water. Shethen titrates this solution with 0.0600M NaOH solution. When the titration reaches the equivalence point, the chemist finds she has added 13.1 mL ofNaOH solution.Calculate the molar mass of the unknown acid. Round your answer to 2 significant digits.mol

Acid - Base titration In acid - base titration at equivalence point M1×V1 = M2×V2 Let, 1 for acid…

An analytical chemist weighs out 0.074 g of an unknown monoprotic acid into a 250 mL volumetric flask and dilutes to the mark with distilled water. She then titrates this solution with 0.0600M NaOH solution. Wwhen the titration reaches the equivalence point, the chemist finds she has added 13.1 mL of NaOH solution. Calculate the molar mass of the unknown acid. Round your answer to 2 significant digits.

An analytical chemist weighs out 0.074 g of an unknown monoprotic acid into a 250 mL volumetric flask and dilutes to the mark with distilled water. She then titrates this solution with 0.0600M NaOH solution. Wwhen the titration reaches the equivalence point, the chemist finds she has added 13.1 mL of NaOH solution. Calculate the molar mass of the unknown acid. Round your answer to 2 significant digits.

Chemistry: The Molecular Science

5th Edition

ISBN:9781285199047

Author:John W. Moore, Conrad L. Stanitski

Publisher:John W. Moore, Conrad L. Stanitski

Chapter1: The Nature Of Chemistry

Section: Chapter Questions

Problem 127QRT

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