An arrow is shot upward from the ground, with an initial velocity of 86 meters per second, at an angle of 46° with respect to the horizontal. The horizontal distance x from the starting point and the height y above the ground of the arrow t seconds after it is shot are given by the parametric eguations below. x-(% cos e)t y=-4.91 +(vo sin e)+h Here v, is the initial velocity, 0 is the initial angle with respect to the horizontal, and h is the initial height. Use the equations to answer the following questions. (a) When does the arrow reach its maximum height? Do not round any intermediate computations. Round your answer to the nearest hundredth. O seconds (b) What is the maximum height of the arrow? Round earest tenth. met

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Projectile Motion