Mole Fraction Solubility Data Obs. y x1 x2 X3 1 0.2220 7.3 0.0 0.0 23456 0.3950 8.7 0.0 0.3 0.4220 8.8 0.7 1.0 0.4370 8.1 4.0 0.2 5 0.4280 9.0 0.5 1.0 6 0.4670 8.7 1.5 2.8 7 0.4440 9.3 2.1 1.0 8 0.3780 7.6 5.1 3.4 9 0.4940 10.0 0.0 0.3 10 0.4560 8.4 3.7 4.1 11 0.4520 9.3 3.6 2.0 12 0.1120 7.7 2.8 7.1 13 0.4320 9.8 4.2 2.0 14 0.1010 7.3 2.5 6.8 15 0.2320 8.5 2.0 6.6 16 0.3060 9.5 2.5 5.0 17 0.0923 7.4 2.8 7.8 18 0.1160 7.8 2.8 7.7 222 19 0.0764 7.7 3.0 8.0 20 0.4390 10.3 1.7 4.2 An article in a reputable science journal presented data on the mole fraction solubility of a solute at a constant temperature. Also measured are the dispersion x₁ and dipolar and hydrogen bonding solubility parameters x2 and x3. A portion of the data is shown in the accompanying table. In the model, y is the negative logarithm of the mole fraction. Complete parts (a) through (c) below. Click the icon to view the mole fraction solubility data. y= -0.269 + (0.078) ×₁ + (0.025) x2 + (-0.036) ×3 (Round to three decimal places as needed.) Determine the alternative hypothesis. H₁: At least one of the coefficients is not 0. Find the test statistic. f= 35.28 (Round to two decimal places as needed.) Find the P-value. P-value = 0.000 (Round to three decimal places as needed.) Determine the proper conclusion. Reject Ho. There is sufficient evidence to conclude that at least one of the coefficients is not zero. (b) Plot the studentized residuals against x₁, x2, and x3. Comment. Plot the studentized residuals against x₁. Choose the correct graph below. A. Stud. Resid. ○ B. Stud. Resid. x1 ☑ ○ C. Stud. Resid. x1 ○ D. Q Stud. Resid. 11 ☑