An artificial intelligence system was design to forecast the financial trading market and predict change В E F Produce the results for depth search from the graph above. eg A to B should be (A,B) b. Produce the values for depth search and breadth search. eg A to B should be (A,B) Produce the adjacency matrix of the graph above. а. с.
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- In C program We want to emulate that, too! Using a recursive function, make it so that we print the number we are currently in on a new line. When we encounter a number n divisible by 5, we print "YEHEY" and jump 7 steps forward. However when we encounter a number divisible by 8, we print "OHNO" and go back 6 steps. If it is divisible by both, we print "LUCKY" and jump 11 steps. Otherwise just move 1 step. Start at n=1 and continue doing this until you reach a number greater than or equal to the number entered by the user. Instructions: In the code editor, you are provided with a main() function that must ask the user for a number and calls the snake_ladder() function.This snake_ladder() function is a recursive function which should perform the functionality explained in the problem description above.This function is declared but is initially empty.Input 1. Stopping number Description Input the number to which the recursive function must stop Constraints The input is a positive integer…for C++ write a progam for the greatest common divisor of integers x and y is the largest integer that evenly divides both x and y. Write a recursive function gcd that returns the greatest common divisor of x and y. The gcd of x and y is defined recursively as follows. If y is 0 the answer is x; otherwise gcd(x, y) is gcd(y, x%y).Check these two codes and then answer these questions please: 1) Empirically, show the performance curve of the algorithm using time measurements 2) Using the basics of the theoretical analysis, write the complexity of its worst-casetime. 1. Approach: Non recursive: //include necessary header files#include <iostream>using namespace std;//main functionint main(){ int days,buy_on_this_day ,sell_on_this_day; //get number of days as input from user cout<<"Enter number of days: "; cin>>days; int stock_price[days]; for(int i=0;i<days;i++) { cout<<"Enter stock_price"; cin>>stock_price[i]; } int i=0; for(int i=0;i<days-1;i++) { //comparing current price with next day price and finding the minima while(i<days-1 && stock_price[i+1]<=stock_price[i]) i++; if(i==days-1) break; buy_on_this_day =i++; while(i<days && stock_price[i]>=…
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