An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 40ft per sec. The height s of the ball in feet is given by the equation s equals negative 2.7 t squared plus 40 t plus 6.5s=−2.7t2+40t+6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b. a. After how many seconds is the ball 20ft above the moon's surface? After 14.47 comma 0.3514.47,0.35 seconds the ball will be 20ft above the moon's surface. (Round to the nearest hundredth as needed. Use a comma to separate answers as needed.) b. How many seconds will it take for the ball to hit the moon's surface?
An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 40ft per sec. The height s of the ball in feet is given by the equation s equals negative 2.7 t squared plus 40 t plus 6.5s=−2.7t2+40t+6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b. a. After how many seconds is the ball 20ft above the moon's surface? After 14.47 comma 0.3514.47,0.35 seconds the ball will be 20ft above the moon's surface. (Round to the nearest hundredth as needed. Use a comma to separate answers as needed.) b. How many seconds will it take for the ball to hit the moon's surface?
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.6: Solving Quadratic Equations By Using The Quadratic Formula
Problem 15CYU
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Question
An astronaut on the moon throws a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is
40ft per sec. The height s of the ball in feet is given by the equation
s equals negative 2.7 t squared plus 40 t plus 6.5s=−2.7t2+40t+6.5,
where t is the number of seconds after the ball was thrown. Complete parts a and b.a. After how many seconds is the ball
20ft above the moon's surface?
After
14.47 comma 0.3514.47,0.35
seconds the ball will be
20ft above the moon's surface.
(Round to the nearest hundredth as needed. Use a comma to separate answers as needed.)
b. How many seconds will it take for the ball to hit the moon's surface?
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