The height of an object that is launched from a 58.8 meter tall building at a velocity of 19.6m/s can be modeled by the equation h(t) = -4.9t2 + 19. 6t + 58. 8 where tis the time in seconds after launch and h is the height of the object above the ground, in meters. The total time that the object is at least 62 meters above the ground would be 0.17 sec O 3.66 sec O 4.00 sec 3.83 sec

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