An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vĄ. Piece B with mass mg travels to the right with speed vB. Show the velocity of piece B in terms of mĄ, mg and VA. Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: PBf + PAf = 0 Substituting the expression for momentum results to mgv mAV = 0 Deriving the expression for the velocity of piece B results to =(mĄ/m VA
An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vĄ. Piece B with mass mg travels to the right with speed vB. Show the velocity of piece B in terms of mĄ, mg and VA. Solution: Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so: PBf + PAf = 0 Substituting the expression for momentum results to mgv mAV = 0 Deriving the expression for the velocity of piece B results to =(mĄ/m VA
College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter28: Special Relativity
Section: Chapter Questions
Problem 67PE: (a) A nuclear power plant converts energy from nuclear fission into electricity with an efficiency...
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Question
An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass mA travels to the left with a speed of vA. Piece B with mass mB travels to the right with speed vB. Show the velocity of piece B in terms of mA, mB and VA.
Solution:
Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so:
pBf + pAf = 0
Substituting the expression for momentum results to
mBv + mAv = 0
Deriving the expression for the velocity of piece B results to
![QUESTION 5
An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vĄ. Piece B with mass
mg travels to the right with speed vg. Show the velocity of piece B in terms of mĄ, mB and VA.
Solution:
Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so:
PBf + PAf = 0
Substituting the expression for momentum results to
mgv
mAV
= 0
Deriving the expression for the velocity of piece B results to
=(ma/m
VA](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b0b4edd-365c-43a6-8f11-a334e9ebe63c%2Fa23d2a8d-8afe-44ff-b82c-8c99478ed71f%2Fddgacns_processed.png&w=3840&q=75)
Transcribed Image Text:QUESTION 5
An atomic nucleus suddenly bursts apart (fission) into two pieces. Piece A with mass ma travels to the left with a speed of vĄ. Piece B with mass
mg travels to the right with speed vg. Show the velocity of piece B in terms of mĄ, mB and VA.
Solution:
Consider that the nucleus is not acted by an external force. Thus, momentum is conserved, so:
PBf + PAf = 0
Substituting the expression for momentum results to
mgv
mAV
= 0
Deriving the expression for the velocity of piece B results to
=(ma/m
VA
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