Greetings and thank you for your help I appreciate youplease write legibly thank youAn automobile with 0.260 m radius tires travels 80,000 kmbefore wearing them out. How many revolutions do the tiresmake, neglecting any backing up and any change in radiusdue to wear? Formula Sheet and Checklist for Circular Motion and GravitationTopicUniform Circular MotionDefinition/FormulaMotion in a circular path with constant speed.Distance traveled by an object along a circularpath.Arc length, AsRotation Angle, AOAsThe RadianLinear Velocity, v2n radians = 1 revolution = 360°Rate of change of arc length with respect toAstime. v =AtAngular Velocity, wRate of change of angle with respectto time.W =AtRelationship between Angular Velocity andLinear VelocityCentripetal Acceleration, acv = rwv2a =a = rw?Centripetal Force, F.mv2F =; F = mrw?%3DInertial Frame of referenceA Frame of Reference moving with constantvelocity.Non-Inertial Frame of referenceAn accelerating Frame of Reference.Fictitious ForceAn unrealforce due to a Non-Inertial Frame ofReference.Centrifugal ForceAn unrealforce due to circular motion.Coriolis ForceA fictitious force observed froma Non - Inertialframe of Reference.Universal Law of GravitationF = Gr2

Number of revolution=distance/2πR As distance covered in 1 revolution=2πR

Answered: An automobile with 0.260 m radius tires…

An automobile with 0.260 m radius tires travels 80,000 km before wearing them out. How many revolutions do the tires make, neglecting any backing up and any change in radius due to wear?

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter7: Gravitation

Section: Chapter Questions

Problem 89A

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