An eccentrically loaded continuous foundation is shown in Figure P6.18. Determine the ultimate load Qu per unit length that the foundation can carry. Use the reduction factor method [Eq. (6.67)]. 6.18 eu y 105 lb/ft3 2 ft Groundwater table ▼ 4 ft %at == 118 lb/ft3 c'=0 d' = 35。 5ft FIGURE P6.18

An eccentrically loaded continuous foundation is shown in Figure P6.18. Determine the ultimate load Qu per unit length that the foundation can carry. Use the reduction factor method [Eq. (6.67)]. 6.18 eu y 105 lb/ft3 2 ft Groundwater table ▼ 4 ft %at == 118 lb/ft3 c'=0 d' = 35。 5ft FIGURE P6.18

Principles of Foundation Engineering (MindTap Course List)

9th Edition

ISBN:9781337705028

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter6: Shallow Foundations: Ultimate Bearing Capacity

Section: Chapter Questions

Problem 6.12P

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Foundation construction

Question

subject : Geotechnical Design

Book : PRINCIPLE OF FOUNDATION ENGINEERING

An eccentrically loaded continuous foundation is shown
in Figure P6.18. Determine the ultimate load Qu per unit
length that the foundation can carry. Use the reduction factor
method [Eq. (6.67)].
6.18
eu
y 105 lb/ft3
2 ft
Groundwater table
▼
4 ft
%at == 118 lb/ft3
c'=0
d' = 35。
5ft
FIGURE P6.18

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