An electric cable is hung between two towers that are 40 meters apart (see figure). The cable takes the shape of a catenary whose equation is as follows, where x and y are measured in meters. y = 10(ex/20 + e-x/20), –20 s x s 20 Find the arc length (in m) of the cable between the two towers. (Round your answer to three decimal places.) 30 10 -20 -10 10 20

Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter65: Achievement Review—section Six
Section: Chapter Questions
Problem 58AR: Solve these prism and cylinder exercises. Where necessary, round the answers to 2 decimal places...
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An electric cable is hung between two towers that are 40 meters apart (see figure). The cable takes the shape of a catenary whose equation is as follows, where x and y are measured in meters.
y = 10(ex/20 + e-x/20), -20< x< 20
Find the arc length (in m) of the cable between the two towers. (Round your answer to three decimal places.)
30
10
-20 –10
10 20
Transcribed Image Text:An electric cable is hung between two towers that are 40 meters apart (see figure). The cable takes the shape of a catenary whose equation is as follows, where x and y are measured in meters. y = 10(ex/20 + e-x/20), -20< x< 20 Find the arc length (in m) of the cable between the two towers. (Round your answer to three decimal places.) 30 10 -20 –10 10 20
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