An electric field given by E = 4.60 i - 4.40(y² + 6.40) j pierces the Gaussian cube of edge length 0.650 m and positioned as shown in the figure. (The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux (Nm²/C) through the cube? 7. Gaussian surface (a) -0.785 (b) -0.895 (c) -1.18 (d) -0.658 (e) None of the above

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter19: Electric Forces And Electric Fields
Section: Chapter Questions
Problem 38P: A particle with charge Q is located a small distance immediately above the center of the flat face...
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An electric field given by E = 4.60 i - 4.40(y² + 6.40) j pierces the Gaussian cube
7.
of edge length 0.650 m and positioned as shown in the figure. (The magnitude E is in
newtons per coulomb and the position x is in meters.) What is the electric flux (Nm²/C)
through the cube?
Gaussian
surface
(a) -0.785 (b) -0.895 (c) -1.18 (d) -0.658 (e) None of the above
Transcribed Image Text:An electric field given by E = 4.60 i - 4.40(y² + 6.40) j pierces the Gaussian cube 7. of edge length 0.650 m and positioned as shown in the figure. (The magnitude E is in newtons per coulomb and the position x is in meters.) What is the electric flux (Nm²/C) through the cube? Gaussian surface (a) -0.785 (b) -0.895 (c) -1.18 (d) -0.658 (e) None of the above
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