I do not understand why the resultant vector doesn't have θ calculated as the angle made by the electron hitting the bottom plate. I found θ = tan-1 (1.7x106 /4x106 ) = 23°. Is this a misunderstanding and it should be 90°?vf=4.35x106 [R23°D] An electron is in motion at 4.0 × 10⁰ m/s horizontally when it enters aregion of space between two parallel plates, as shown, starting at thenegative plate. The electron deflects downwards and strikes the bottomplate. The magnitude of the electric field between the plates is 4.0 x 10²N/C and separation between the charged plates is 2.0 cm.1AAAAADetermine the velocity of the electron as it strikes the plate.d = 2.0 cm

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Answered: An electron is in motion at 4.0 × 10⁰…

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.46P: A thin, square, conducting plate 50.0 cm on a side lies in the xy plane. A total charge of 4.00 108...

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I do not understand why the resultant vector doesn't have θ calculated as the angle made by the electron hitting the bottom plate. I found θ = tan^-1 (1.7x10⁶ /4x10⁶ ) = 23°. Is this a misunderstanding and it should be 90°?

v_f=4.35x10⁶_[R23°D]

An electron is in motion at 4.0 × 10⁰ m/s horizontally when it enters a
region of space between two parallel plates, as shown, starting at the
negative plate. The electron deflects downwards and strikes the bottom
plate. The magnitude of the electric field between the plates is 4.0 x 10²
N/C and separation between the charged plates is 2.0 cm.
1
AAAAA
Determine the velocity of the electron as it strikes the plate.
d = 2.0 cm

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